The table below shows two equations:

1 answer:

7 0

This problem can be solved by using the answer choices. We plug in the given values of the equations and see if they satisfy it.
| 4(3) - 3 | - 5 = 4
4 = 4; this is a solution
| 4(-1.5) - 3 | - 5 = 4
4 = 4; this is a solution

|2(-4) + 3| + 8 = 3
13 =/= 3, not a solution

|2(1) + 3| + 8 = 3
13 =/= 3, not a solution

Thus, equation 1 has two solutions, x = 3 and x = -1.5, while equation 2 has no solutions. The third option is correct.

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How many extraneous solutions does the equation below have? StartFraction 9 Over n squared 1 EndFraction = StartFraction n 3 Ove

BigorU [14]

The equation has one extraneous solution which is n ≈ 2.38450287.

Given that,

The equation;

$\dfrac{9}{n^2+1} =\dfrac{n+3}{4}$

We have to find,

How many extraneous solutions does the equation?

According to the question,

An extraneous solution is a solution value of the variable in the equations, that is found by solving the given equation algebraically but it is not a solution of the given equation.

To solve the equation cross multiplication process is applied following all the steps given below.

$\rm \dfrac{9}{n^2+1} =\dfrac{n+3}{4}\\\\9 (4) = (n+3) (n^2+1)\\\\36 = n(n^2+1) + 3 (n^2+1)\\\\36 = n^3+ n + 3n^2+3\\\\n^3+ n + 3n^2+3 - 36=0\\\\n^3+ 3n^2+n -33=0\\$