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2 years ago

The table below shows two equations:

1 answer:

7 0

This problem can be solved by using the answer choices. We plug in the given values of the equations and see if they satisfy it.
| 4(3) - 3 | - 5 = 4
4 = 4; this is a solution
| 4(-1.5) - 3 | - 5 = 4
4 = 4; this is a solution

|2(-4) + 3| + 8 = 3
13 =/= 3, not a solution

|2(1) + 3| + 8 = 3
13 =/= 3, not a solution

Thus, equation 1 has two solutions, x = 3 and x = -1.5, while equation 2 has no solutions. The third option is correct.

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3 years ago

Read 2 more answers

Jamarius buys T-shirts for $6 each and marks up the price by 45%. How much profit does Jamarius make from each T-shirt sold?

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Answer:

$2.70

Step-by-step explanation:

To add 45 percent to the original price you do 100%+45%=145%=1.45

times 1.45 by the original price.

Then take away the original price from the answer you just got.

$1.45×$6=$8.70

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3 years ago

Solve the given system of equations using either Gaussian or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTI

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Answer:

The system has infinitely many solutions

$\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}$

Step-by-step explanation:

Gauss–Jordan elimination is a method of solving a linear system of equations. This is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.

An Augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

There are three elementary matrix row operations:

Switch any two rows
Multiply a row by a nonzero constant
Add one row to another

To solve the following system

$\begin{array}{ccccc}x_1&-3x_2&-2x_3&=&0\\-x_1&2x_2&x_3&=&0\\2x_1&+3x_2&+5x_3&=&0\end{array}$

Step 1: Transform the augmented matrix to the reduced row echelon form

$\left[ \begin{array}{cccc} 1 & -3 & -2 & 0 \\\\ -1 & 2 & 1 & 0 \\\\ 2 & 3 & 5 & 0 \end{array} \right]$

This matrix can be transformed by a sequence of elementary row operations

Row Operation 1: add 1 times the 1st row to the 2nd row

Row Operation 2: add -2 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1

Row Operation 4: add -9 times the 2nd row to the 3rd row

Row Operation 5: add 3 times the 2nd row to the 1st row

to the matrix

$\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]$

The reduced row echelon form of the augmented matrix is

$\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]$

which corresponds to the system

$\begin{array}{ccccc}x_1&&-x_3&=&0\\&x_2&+x_3&=&0\\&&0&=&0\end{array}$

The system has infinitely many solutions.

$\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}$

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3 years ago

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Answer:

Domain = x E R

Step-by-step explanation:

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