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Nutka1998 [239]
3 years ago
11

The table below shows two equations:

Mathematics
1 answer:
Amanda [17]3 years ago
7 0
This problem can be solved by using the answer choices. We plug in the given values of the equations and see if they satisfy it.
| 4(3) - 3 | - 5 = 4
4 = 4; this is a solution
| 4(-1.5) - 3 | - 5 = 4
4 = 4; this is a solution

|2(-4) + 3| + 8 = 3
13 =/= 3, not a solution

|2(1) + 3| + 8 = 3
13 =/= 3, not a solution

Thus, equation 1 has two solutions, x = 3 and x = -1.5, while equation 2 has no solutions. The third option is correct.
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The chamber of commerce for a beach town asked a random sample of city-dwellers, "Would you like to live at the beach?” Based on
Dvinal [7]

Answer:

Ummm... ya its a becasue 95 is more then 50 (brainlest plzzzzzzzzzzzzzz)

Step-by-step explanation:

6 0
3 years ago
Please help! How on earth do I do this? In the year 2015, Anna bought a new car for $36,000. In 2017, she was told that the valu
Klio2033 [76]

Part A

Purchase Value of Anna's Car in 2015 = $36,000

Depreciated Value of Anna's Car in 2017 = $25,000

We know that the value of the car is depreciating linearly.


From the above data, we can see that the value of the car has reduced by $36,000-$25,000 = $11,000 over 2 years.

⇒ Per year the value has been depreciated by \frac{11000}{2}

⇒ Per year the value has been depreciated by $5,500

So if the value of a car in 2015 is V₀ then value of the car after t years can be determined by the below function:

V (t) = V₀ - (t*5,500), where t indicates the years passed since 2015

OR V (t) = 36,000 - (t*5,500), where t indicates the years passed since 2015

Part B

Suggested value of Anna's car for trade in option in 2018 = $15,000

In 2018, 3 years would have been passed since 2015. Using the value of t = 3 in the function determined in Part A:

V(3) = V₀ - (3*5,500)

⇒ V(3) = 36,000 - (16,500)

⇒ V(3) = $19,000

From the above calculations, we can see that the value of the car in 2018 should be $19,000, however the suggested value for trade in is indicated as $15,000 which is lower than what the value of the car should be. Hence, basis linear depreciation, the $15,000 value is not fair for the car in 2018.

3 0
3 years ago
Find the area of a regular decagon with perimeter 100 units. Show all work.
Slav-nsk [51]
A regular polygon has ten (10) equal sides ( since it is regular).
We are given with the perimeter value which is 100 units and the perimeter formula is P = 10a
Solving for a (the side measurement), we have:
100 = 10a
a= 100/10
a =10

We can now proceed in solving the area and the formula is shown below:
Area = 5/2 a√ (5+2√5)
Area = 5/2 * 10√(5+2√5)
Area = 76.94 square units

The answer is 96.94 square units.
4 0
3 years ago
Solve the system of equations.<br> y= 3x<br> y= x2-10
svetoff [14.1K]

Answer:

(-5, 2) and (2, 6)

Step-by-step explanation:

Use the substitution method. We know that y = 3x and y = x^2 - 10, so we can set them equal to one another.

3x = x^2 - 10

x^2 - 3x - 10 = 0

Use the quadratic equation to solve for x.

x = - 5, 2

Now solve for y using these two values of x by substituting it back into the equations.

y = - 15,  6

In coordinate form, (-5, 2) and (2, 6)

7 0
3 years ago
Can someone check my answer? Is it B? Thanks!
zloy xaker [14]
Solution is where the 2 lines intersect

I would say the answer is 3rd option, whre both lines pass through that point
8 0
3 years ago
Read 2 more answers
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