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Lyrx [107]
3 years ago
6

Solution of inequality -2/5x-9<9/10

Mathematics
1 answer:
Phantasy [73]3 years ago
5 0
- \frac{2}{5}x-9\ \textless \  \frac{9}{10}   \\(- \frac{2}{5}x-9\ \textless \  \frac{9}{10} )*10 \\ -4x-90\ \textless \ 9 \\ -4x\ \textless \ 9+90 \\ x\ \textgreater \  -\frac{99}{4}
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PLS HELP MEEEEEEEEEEEEEEEEEEEEE PLS I BEG U
Luden [163]

The fact that a connection is proportional if its graph is a line that runs through its origin should be stressed. This can be used to find the ratio in the proportional relationship.

<h3>How to explain the information?</h3>

When the graph of a connection is a line passing through the origin, the connection is proportionate. If it is not a line or ray that fails to do this, the ratio is not proportional. The equation for the proportionality constant is K = y/x. This is the same equation used to get the slope of a straight line with respect to the origin.

If the graph of a relationship is a line or ray that goes through the origin, the relationship is proportional. If the line or ray does not pass through the origin, it is not proportional.

Learn more about graph on:

brainly.com/question/19040584

#SPJ1

4 0
1 year ago
Helppp.... don’t understand
sveticcg [70]
The answer is C.

Steps:
(6.77 x 10^4) - (5.21 x 10^3)
(6.77 x 10^4) - (.521 x 10^4)
6.77 - .521 = 6.249
(6.249 x 10^4)

Hope this helps
5 0
3 years ago
What is the slope if y=5
Archy [21]

Answer:

0

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
50 POINTS FIRST GOOD ANSWER GETS BRAINLIEST
Inessa [10]

Answer:

f(x)=3+|2x-5|=\left\{        \begin{array}{ll}            2x-2& \quad x \geq 5/2 \\            -2x+8 & \quad x < 5/2         \end{array}    \right.

Step-by-step explanation:

We are given the function:

f(x)=3+|2x-5|

Remember that by the definition of absolute value:

\displaystyle |x|= \left\{        \begin{array}{ll}            x & \quad x \geq 0 \\        -    x & \quad x < 0        \end{array}    \right.

Our absolute value is:

|2x-5|

First, we will find when it becomes 0. Set the equation equal to 0:

2x-5=0

Solve for <em>x: </em>

<em />x=5/2<em />

<em />

So, we can see that for all values greater than <em>x </em>= 5/2, 2x - 5 is positive.

For all values less than <em>x </em>= 5/2, 2x - 5 is negative.

Therefore (the positive case go above, and the negative case go below):

|2x-5|= \left\{        \begin{array}{ll}            2x-5 & \quad x \geq 5/2 \\           -(2x-5) & \quad x < 5/2         \end{array}    \right.

Finally, we can add a three:

f(x)=3+|2x-5|=\left\{        \begin{array}{ll}            3+(2x-5) & \quad x \geq 5/2 \\            3+(-(2x-5)) & \quad x < 5/2        \end{array}    \right.

Simplify if desired:

f(x)=3+|2x-5|=\left\{        \begin{array}{ll}            2x-2& \quad x \geq 5/2 \\            -2x+8 & \quad x < 5/2         \end{array}    \right.

5 0
3 years ago
In the standard normal curve, the mean is____ and a standard deviation of ____ .
mariarad [96]

Answer:

Standard normal curve is 0.

Standard deviation is 1.

3 0
3 years ago
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