Given:
Q = 0.0764 kJ = 764 J, heat input
W = -830 J, useful work done
From the 1st Law of Thermodynamics, the change in internal energy is
δE = Q - W
= 764 - (-830)
= 1594 J = 1.594 kJ
Answer: 1.59 kJ (two sig. fig.)
Answer:
its B
Step-by-step explanation: its the only one with the 2 so its the right answer
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Answer:
<em>1</em><em>.</em><em> </em>cos (P) = StartFraction r Over q EndFraction
<em>2</em><em>.</em>cos (R) = StartFraction p Over q EndFraction
Step-by-step explanation:
1.
2.