Lowest common multiple of 8 and 56

Mathematics

1 answer:

Gnom [1K]3 years ago

6 0

LCM would have to be 2 I think

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Adult tickets to a basketball game cost $5. Student tickets cost $1. A total of $3,169 was collected on the sale of 1,325 ticket

eimsori [14]

Answer:

461 adults and 864 students

Step-by-step explanation:

We can set-up a system of equations to find the number of adults. We know students and adults attended. We will let s be the number of students and a be the number of adults. Since 1,325 tickets were purchased, then s+a=1325.

We also know that a total of $3,169 was collected and adult tickets cost $5 each and students cost $1 each. We can write 1s+5a=3169.

We will solve by substituting one equation into the other. We first solve the first equation for s which is s=1325-a. Substitute s=1325-a into 1s+5a=3169. Simplify and isolate the variable a.

1(1325-a)+5a=3169

1325-a+5a=3169

1325+4a=3169

1325-1325+4a=3169-1325

4a=1844

a=461

This means that 461 adults attended and 864 students attended since 864+461=1325.

8 0

3 years ago

Lloyd is arranging his science project, math project, and art project on his desk. The tree diagram below shows the sample space

Margarita [4]

The tree diagram is constructed and attached below in the image.

First we have to make a choice out of 3 subjects, so the probability of choosing art as the first subject is 1/3.

Once we have chosen art as the first subject, we have two choices. So the probability of choosing each option now is 1/2. Thus, the probability of choosing math, science is 1/2.

The probability of choosing the projects in order of art, math, science = 1/3 x 1/2 = 1/6

Therefore, the probability that the projects are in order of art, math, science is 1/6 (one over 6). So first option gives the correct answer.