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iragen [17]
4 years ago
12

How do you count by 36

Mathematics
2 answers:
AlekseyPX4 years ago
6 0
You count by 36 by adding at 36 every time u go up : 

36, 72, 108,144 , 180 etc
Inga [223]4 years ago
5 0
6, 12, 18, 24, 30, 36

36, 72, 108, 144, 180, 216

4, 8, 12, 16, 20, 24, 28, 32, 36
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This week Andres will practice with his band for 1 1\2 hours monday , 1 3\4 hours on tuesday , and 2 hours wednesday . Next week
alexdok [17]

Answer:

10.5 hours

Step-by-step explanation:

Given:

This week Andres will practice with his band for

1\frac{1}{2} \ means\ \frac{3}{2} \ hours on Monday

1\frac{3}{4} \ means\ \frac{7}{4} \ hours  on Tuesday

2 hours Wednesday.

Next week Andres will practice with his band for the same number of hours on Monday, Tuesday, Wednesday.

<u>Question</u> <u>asked</u>:

What was the total number of hours Andres will practice with his band over these 6 days?

<u>Solution</u>:

As she practice for two weeks, three days of each week:

On two Monday, she will practice = \frac{3}{2} + \frac{3}{2} =\frac{3+3}{2} =\frac{6}{2} =3\ hours

On two Tuesday, she will practice = \frac{7}{4} +\frac{7}{4}=\frac{7+7}{4} =\frac{14}{4} =\frac{7}{2} \ hours

On two Wednesday, she will practice = 2+2=4 \ hours

Total hours, she will practice over 6 days  =3+\frac{7}{2} +4

                                                                      =7+\frac{7}{2} \\ \\ =\frac{2\times7+7}{2} \\ \\ =\frac{21}{2} \\ \\ =10.5\ hours

Thus, Andres will practice 10.5 hours with his band over these 6 days.

5 0
3 years ago
Answer this question please and thank you
Georgia [21]

0.377 + 5.51 = 5.887

Sorry I can only solve the first one. Could you give me a hint on how to do the second one ?

5 0
3 years ago
Read 2 more answers
ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing. Show your work or give an explaination.
Romashka-Z-Leto [24]

Answer:

C

Step-by-step explanation:

y = -f(x) is the reflection about the x-axis of the graph y = f(x).

3 0
3 years ago
Solve cos x - square 1-3 cos^2 x = 0 given that 0° &lt; x &lt; 360°
Furkat [3]

Rearrange the equation as

cos(x) - √(1 - 3 cos²x) = 0

cos(x) = √(1 - 3 cos²x)

Note that both sides have to be positive, since the square root function is non-negative. If we end up with any solutions that make cos(x) < 0, we must throw them out.

Take the square of both sides.

(cos(x))² = (√(1 - 3 cos²(x))²

cos²(x) = 1 - 3 cos²(x)

4 cos²(x) = 1

cos²(x) = 1/4

cos(x) = ± √(1/4)

cos(x) = ± 1/2

We throw out the negative case and we're left with

cos(x) = 1/2

This has general solution

x = arccos(1/2) + 360° n   or   x = -arccos(1/2) + 360° n

(where n is any integer)

x = 60° + 360° n   or   x = -60° + 360° n

Now just pick out the solutions that fall in the interval 0° ≤ x < 360°.

• From the first solution set, we have x = 60° when n = 0.

• From the second set, we have x = 300° when n = 1.

So the answer is D.

4 0
3 years ago
Segment BDSegment BD is a perpendicular bisector of segment ACsegment AC . AB=6xAB=6x and CB=x+15CB=x+15 . What is the length of
jolli1 [7]
Since BD is the perpendicular bisector of AC, then AB = BD, so:
6x = x+15
5x=15
x=3
CB = 3+15 = 18
3 0
3 years ago
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