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3 years ago

12

Determine la ecuación de la recta normal a la curva f(x)=ax(bx+a) en el punto de abscisa x=1. Dar como respuesta el intercepto a

l Eje Y . Considere el valor de a=7 ,b=10

1 answer:

AysviL [449]3 years ago

3 0

Answer:

$f(x) = ax(bx + a) \\ a = 1 \: b = 10 \: x = 1 \\ f(x) = ax(bx + a) \\ f(1) = 7(1)(10(1) + 7) \\ f(1)= 7(10 + 7) \\ f(1)= 70 + 49 \\ f(1)= 149$

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