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GREYUIT [131]
3 years ago
12

Determine la ecuación de la recta normal a la curva f(x)=ax(bx+a) en el punto de abscisa x=1. Dar como respuesta el intercepto a

l Eje Y . Considere el valor de a=7 ,b=10
Mathematics
1 answer:
AysviL [449]3 years ago
3 0

Answer:

f(x) = ax(bx + a) \\ a = 1 \: b = 10 \: x = 1 \\ f(x) = ax(bx + a) \\ f(1) = 7(1)(10(1) + 7) \\   f(1)= 7(10 + 7) \\  f(1)= 70 + 49 \\  f(1)= 149

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Points on given line = (-12,-2) and (0,-4) because you can see them on the graph.  Then draw a parallel line thru (0,6)

To get from (0,-4) to (0,6) your x stays constant and your y coordinate increased by 10.  So your new point will do the same in relation to (-12,-2)  the x will stay constant at -12 and your y will increase by 10 to +8.  

So the answer is A (-12,8)

You can check this because parallel lines have the same slope so

y2-y1/x2-x1 should be equal for both lines.

Line 1:  -4 - (-2) / 0 - (-12) = -2/12 = -1/6

Line 2:  6 - 8 / 0 - (-12) = -2/12 = -1/6


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