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3 years ago

12

Determine la ecuación de la recta normal a la curva f(x)=ax(bx+a) en el punto de abscisa x=1. Dar como respuesta el intercepto a

l Eje Y . Considere el valor de a=7 ,b=10

1 answer:

AysviL [449]3 years ago

3 0

Answer:

$f(x) = ax(bx + a) \\ a = 1 \: b = 10 \: x = 1 \\ f(x) = ax(bx + a) \\ f(1) = 7(1)(10(1) + 7) \\ f(1)= 7(10 + 7) \\ f(1)= 70 + 49 \\ f(1)= 149$

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Given P(A) = 0.072, P(B) = 0.180, and P(C) = 0.027, and that events A, B, and C are mutually exclusive, what is the P(A or B or

9966 [12]

Given P(A) = 0.072, P(B) = 0.180, and P(C) = 0.027, and that events A, B, and C are mutually exclusive,then P(A or B or C) is 0.279

<u>Solution: </u>

Given that probability of event A is P(A) = 0.072

Probability of event B is P(B) = 0.180

Probability of event C is P(C) = 0.027

Also event A, B and C are mutually exclusive.

Need to determine P( A or B or C )

For mutually exclusive events

P( A or B or C ) = P(A) + P(B) + P(C)

= 0.072 + 0.180 + 0.027 = 0.279

Hence probability of occurrence of event A or event B or event C , where A , B and C are mutually exclusive events is 0.279.

5 0

2 years ago

Which expression is equivalent to 2(u+4)?<br> 2u+8<br> 8u+2<br> 8u<br> 6u

irga5000 [103]

Answer:

2u + 8

General Formulas and Concepts:

<u>Pre-Algebra</u>

Distributive Property

Step-by-step explanation:

<u>Step 1: Define</u>

2(u + 4)

<u>Step 2: Expand</u>

Distribute 2: 2(u) + 2(4)
Multiply: 2u + 8

4 0

2 years ago

X and y=540 when X=10, find y when x=1/2

soldier1979 [14.2K]

Answer:

y = 27

Step-by-step explanation:

if x = 10 when y = 540 , y = 54x

if x = 1/2 y = 54*1/2 = 27

y = 27

4 0

3 years ago

a volley ball player servers the ball. The ball follows a path given by the equation y=-0.01x^2+0.5x+3 where x and y are measure

dolphi86 [110]

Answer:

(a)

Distance from player should be 13.82 feet or 36.2 feet

(b)

The ball will go over the net

Step-by-step explanation:

we are given

The ball follows a path given by the equation

$y=-0.01x^2+0.5x+3$

where

x and y are measured in feet and the origin is on the court directly below where the player hits the ball

(a)

net height is 8 ft

so, we can set y=8

and then we can solve for x

$8=-0.01x^2+0.5x+3$

$8\cdot \:100=-0.01x^2\cdot \:100+0.5x\cdot \:100+3\cdot \:100$

$800=-x^2+50x+300$

$-x^2+50x-500=0$

$x^2-50x+500=0$

we can use quadratic formula

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-50\pm \sqrt{50^2-4\left(-1\right)\left(-500\right)}}{2\left(-1\right)}$

$x=5\left(5-\sqrt{5}\right),\:x=5\left(5+\sqrt{5}\right)$

$x=13.82,x=36.2$

So, distance from player should be 13.82 feet or 36.2 feet

(b)

we can plug x=30 and check whether y=8 ft

$y=-0.01(30)^2+0.5(30)+3$

$y=9ft$

we know that

height of net is 8 ft

so, the ball will go over the net

5 0

3 years ago

Arte-miy333 [17]

Let x equal the number of adult tickets sold.

X + 3X=512
(I put 3x because we know the students sold 3 times as many).
Solve for X.

X+3X=512
4X=512
4X/4=512/4
X=128

3 0

3 years ago