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3 years ago

1 5/16 + 1 5/16=_____

Mathematics

1 answer:

algol133 years ago

5 0

Answer:

2 10/16 or 2 5/8

Step-by-step explanation:

You can add the whole numbers first, so 1+1=2

Now add the remaining fractions: 5/16 +5/16=10/16.

2+10/16=2 10/16 or 2 5/8.

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Midori cleans the hamster cage every 7 days, brushes the dog every 9 days, and cleans the frog aquarium

Shtirlitz [24]

Answer:

126

Step-by-step explanation:

The least common multiple of 7, 9, and 6 is the product of the unique factors.

7 = prime

9 = 3^2

6 = 3·2

The LCM is 7·3^2·2 = 126

Midori will take care of all three pets again after 126 days.

8 0

4 years ago

Find the product find the product

grandymaker [24]

Answer:

25x^2 -40x + 16

Step-by-step explanation:

(5x-4)^2

(5x-4)(5x-4)

FOIL

first 5x*5x =25x^2

outer 5x*-4 = -20x

inner 5x*-4 = -20x

last = -4*-4 = 16

Add them together

25x^2 -20x -20x+ 16

Combine like terms

25x^2 -40x + 16

6 0

3 years ago

Read 2 more answers

3x-2 when x=-2 whats the answer

Hoochie [10]

Answer:

$3x - 2 \\ 3( - 2) - 2 \\ - 6 - 2 \\ - 8 .answer$

Step-by-step explanation:

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7 0

3 years ago

Read 2 more answers

Annabelle and Navene are multiplying (4 to the power of 2•7 to the power of 5)(4 to the power of3•7 to the power of 2).

lyudmila [28]

$\bf (4^27^5)(4^37^2)\implies 4^27^54^37^2\\\\\\ 4^24^37^57^2\implies 4^{2+3}7^{5+2}\implies 4^57^7$

6 0

3 years ago

Please help me anyone i need this in 10 minutes

Radda [10]

Given:

The rate of interest on three accounts are 7%, 8%, 9%.

She has twice as much money invested at 8% as she does in 7%.

She has three times as much at 9% as she has at 7%.

Total interest for the year is $150.

To find:

Amount invested on each rate.

Solution:

Let x be the amount invested at 7%. Then,

The amount invested at 8% = 2x

The amount invested at 9% = 3x

Total interest for the year is $150.

$x\times \dfrac{7}{100}+2x\times \dfrac{8}{100}+3x\times \dfrac{9}{100}=150$

Multiply both sides by 100.

$7x+16x+27x=15000$

$50x=15000$

Divide both sides by 50.

$x=\dfrac{15000}{50}$

$x=300$

The amount invested at 7% is $300$ .

The amount invested at 8% is

$2(300)=600$

The amount invested at 9% is

$3(300)=900$

Therefore, the stockbroker invested $300 at 7%, $600 at 8%, and $900 at 9%.

6 0

3 years ago