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notka56 [123]
3 years ago
8

Which transformation causes the described change in the graph of the function y = cos x? The transformation results in a horizon

tal shrink. The transformation results in a vertical stretch. The transformation results in a horizontal stretch. The transformation results in a vertical shrink.

Mathematics
1 answer:
Gala2k [10]3 years ago
7 0
First lets look at our graph of y = cos x
***First picture***

Next lets look at a <span>vertical stretch.
***Second picture***

To vertically stretch y = cos x, we need to multiply cos by a number greater than 1. I am going to use 2.

Standard Form: y = cos x (Red Line)
Vertical Stretch: y = 2 cos x (Blue Line)

Lets look at a vertical shrink
***Third picture***

To create a vertical shrink, you multiply the cos by a number less than 1. I am going to use .5

</span>Standard Form: y = cos x (Red Line)
Vertical Shrink: y = .5 cos x (Green Line)

Now lets look at horizontal stretch.
***Forth picture.***

To create a horizontal stretch, you multiply the x by a value less than 1. I am going to use .5

Standard Form: y = cos x (Red Line)
Vertical Stretch: y = .5 cos x (Orange Line)

Finally, to create a horizontal shrink, you multiply the x by a value greater than 1. I am going to use 2.
***Fifth picture.***

Standard Form: y = cos x (Red Line)
Vertical Shrink: y = 2 cos x (Purple Line)

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Answer:

2rr

Step-by-step explanation:

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fgiga [73]

Answer:

y=x+12

Step-by-step explanation:

Well the slope is -4/-4 =1

We plug it into the formula, y=mx+b, but m=1

So it is y=1x+b

We know the points, so we plug y and x in which is:

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b=12

So the point slope form of that is y=x+12

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3 years ago
Simplify <img src="https://tex.z-dn.net/?f=%28r%5Cfrac%7B1%7D%7B2%7D4" id="TexFormula1" title="(r\frac{1}{2}4" alt="(r\frac{1}{2
Katena32 [7]

Hello!!

════ ⋆★⋆ ════

\mathbb{A~N~S~W~E~R~:}

= r · 2

➡ \Huge \sf \mathbb \color{}\underline{\colorbox{ANSWER~WITH~EXPLANATION ~!}{}}

\mathfrak{apply~the~fraction~rule:  }   a \frac{b}{c} =\frac{a~. ~b }{c}

\mathfrak{apply~rule:  }  a · 1 = a

r · 1 · 4 = r · 4

=\frac{r~.~4}{2}

\mathfrak{divide~the~numbers~:  } \frac{4}{2} = 2

= r · 2

So, your answer will be is :

= r · 2

\color{}{Hope\:it\:helps. ..}

#LearnWithBrainly

\mathbb{A~N~S~W~E~R~:}

\mathfrak{Jace}

4 0
3 years ago
(2x² - 5x-3)/ (x-3)<br> DIvide the polynomials
Anika [276]

Answer:

2x + 1

Step-by-step explanation:

\frac{(2x² - 5x-3)}{(x - 3)}

Factor out 2x² - 5x-3

\frac{(2x + 1)(x - 3)}{x - 3}

divide x - 3 by x - 3

=> 2x + 1

<em><u>Or another step</u></em>

Step by Step Solution

STEP

1

:

Equation at the end of step 1

STEP

2

:

2x² - 5x - 3/ x - 3

Trying to factor by splitting the middle term

2.1 Factoring 2x² - 5x - 3

The first term is, 2x² its coefficient is 2 .

The middle term is, -5x its coefficient is -5 .

The last term, "the constant", is -3

Step-1 : Multiply the coefficient of the first term by the constant 2 • -3 = -6

Step-2 : Find two factors of -6 whose sum equals the coefficient of the middle term, which is -5 .

-6 + 1 = -5 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -6 and 1

2x² - 6x + 1x - 3

Step-4 : Add up the first 2 terms, pulling out like factors :

2x • (x-3)

Add up the last 2 terms, pulling out common factors :

1 • (x-3)

Step-5 : Add up the four terms of step 4 :

(2x+1) • (x-3)

Which is the desired factorization

Canceling Out :

2.2 Cancel out (x-3) which appears on both sides of the fraction line.

Final result :

2x + 1

6 0
2 years ago
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