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notka56 [123]
3 years ago
8

Which transformation causes the described change in the graph of the function y = cos x? The transformation results in a horizon

tal shrink. The transformation results in a vertical stretch. The transformation results in a horizontal stretch. The transformation results in a vertical shrink.

Mathematics
1 answer:
Gala2k [10]3 years ago
7 0
First lets look at our graph of y = cos x
***First picture***

Next lets look at a <span>vertical stretch.
***Second picture***

To vertically stretch y = cos x, we need to multiply cos by a number greater than 1. I am going to use 2.

Standard Form: y = cos x (Red Line)
Vertical Stretch: y = 2 cos x (Blue Line)

Lets look at a vertical shrink
***Third picture***

To create a vertical shrink, you multiply the cos by a number less than 1. I am going to use .5

</span>Standard Form: y = cos x (Red Line)
Vertical Shrink: y = .5 cos x (Green Line)

Now lets look at horizontal stretch.
***Forth picture.***

To create a horizontal stretch, you multiply the x by a value less than 1. I am going to use .5

Standard Form: y = cos x (Red Line)
Vertical Stretch: y = .5 cos x (Orange Line)

Finally, to create a horizontal shrink, you multiply the x by a value greater than 1. I am going to use 2.
***Fifth picture.***

Standard Form: y = cos x (Red Line)
Vertical Shrink: y = 2 cos x (Purple Line)

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Let's call the event of the red die to show a six as event A, and the event of the green die to show a six as event B.

The theoretical probability is defined as the ratio of the number of favourable outcomes to the number of possible outcomes. On both dices, we have 6 possible outcomes(the numbers from 1 to 6), with one favourable outcome(the number 6), therefore, the probabilities of those events are:

P(A)=P(B)=\frac{1}{6}

Each roll is independent from each other, then, the probability of both events happening simultaneously is given by their product:

P(A\:and\:B)=P(A)P(B)

Using the additive rule of probability, we have the following equation for our problem:

\begin{gathered} P(A\:or\:B)=P(A)+P(B)-P(A\:and\:B) \\ =P(A)+P(B)-P(A)P(B) \\ =\frac{1}{6}+\frac{1}{6}-\frac{1}{6^2} \\ =\frac{2}{6}-\frac{1}{36} \\ =\frac{12}{36}-\frac{1}{36} \\ =\frac{12-1}{36} \\ =\frac{11}{36} \end{gathered}

the probability that the red die shows a six or the green die shows a six is 11/36.

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1 year ago
Please help! I’ll mark as brainliest
Talja [164]

Answer:

see below

Step-by-step explanation:

domain is all x values for which a graph has
and range is all y values for which a graph has

domain in this case is -4<x<4. The range is -3<= x <= 3

Function is increasing when slope of the line is positive, function is decreasing when slope of the line is negative.

When 2 lines meet and there is an edge like at (-1,3) there is no increase of decrease of the function. If you are in calculus, this is because the derivative of the function will not be valid at those points. If you are not in calculus, then don't pay attention to the derivative stuff.

Function is increasing on interval -4<x<-1 and 2<x<4
Function is decreasing on interval -1<x<2

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Step-by-step explanation:

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