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Ilia_Sergeevich [38]
3 years ago
6

What is te value of f(2)

Mathematics
2 answers:
Makovka662 [10]3 years ago
7 0

Answer:

f(2) = 1

Step-by-step explanation:

f(x) where x = 2

we plug this into the function named f(x) and solve with the value plugged in

f(2) 1/2(2) = 1

Damm [24]3 years ago
5 0

Answer:

\large\boxed{f(2)=1;\ f^{-1}(1)=2;\ f^{-1}(f(2))=2}

Step-by-step explanation:

We have:

f(x)=\dfrac{1}{2}x and f^{-1}(x)=2x

f(2) → put x = 2 to the equation of a function f(x):

f(2)=\dfrac{1}{2}(2)=1

f⁻¹(1) → put x = 1 to the equation of a function f⁻¹(x):

f^{-1}(1)=2(1)=2

f⁻¹(f(2)) → put f(2) = 2 to the equation of a function f⁻¹(x):

f^{-1}(f(2))=f^{-1}(1)=2

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8t – 13t + 10 (t – 2) = 34
MrRa [10]

Answer:

t=10.9

Step-by-step explanation:

8t-13t+10(t-2)=34

8t-13t+10t-20=34

5t-20=34

5t=54

t=10.9

3 0
3 years ago
The sum of two binomials is 5x^2-6x . If one of the binomials is3x^2-2x , what is the other binomial?
vlada-n [284]
Its 2x^2-4x, to check it add it to 3x^2-2x or
2x^(2)-4x+3x^(2)-2x
6 0
3 years ago
What are the coordinates of the image of C if it is reflected across the x-axis?
Svetradugi [14.3K]

Answer:

(-2, 4)

Step-by-step explanation:

~When reflecting a point of the x-axis, the x value (or first number inside the parenthesis) does not change.

The reason the x-value does not change is because you are reflecting over the x-axis, making the point go up or down. That will change the y-value but the x-value only changes if you move to the left or the right. In this case, you can see that the point's x-value is -2, so that will not change. It's current y-value however is -4. When reflecting over an axis, the number that is changing (in this case the y-value) will just be flipped from positive to negative, or vise versa. In this case, -4 will be reflected to be 4, making point C reflected over the x-axis (-2, 4).

5 0
3 years ago
Read 2 more answers
Factor 9x^2+66xy+121y^2
Korvikt [17]
Answer: (3x + 11y)^2

Demonstration:

The polynomial is a perfect square trinomial, because:

1) √ [9x^2] = 3x

2) √121y^2] = 11y

3) 66xy = 2 *(3x)(11y)

Then it is factored as a square binomial, being the factored expression:

 [ 3x + 11y]^2

Now you can verify working backwar, i.e expanding the parenthesis.

Remember that the expansion of a square binomial is:

- square of the first term => (3x)^2 = 9x^2
- double product of first term times second term =>2 (3x)(11y) = 66xy
- square of the second term => (11y)^2 = 121y^2

=> [3x + 11y]^2 = 9x^2 + 66xy + 121y^2, which is the original polynomial.

7 0
3 years ago
Solve System Below<br><br> 5x + 8y = 3<br> 5x + 9y = 3
Aleks04 [339]

Answer:

Step-by-step explanation:

-5x - 8y = -3

5x + 9y = 3

y = 0

5x + 0 = 3

5x = 3

x = 3/5

(3/5, 0)

5 0
3 years ago
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