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Ilia_Sergeevich [38]
4 years ago
6

What is te value of f(2)

Mathematics
2 answers:
Makovka662 [10]4 years ago
7 0

Answer:

f(2) = 1

Step-by-step explanation:

f(x) where x = 2

we plug this into the function named f(x) and solve with the value plugged in

f(2) 1/2(2) = 1

Damm [24]4 years ago
5 0

Answer:

\large\boxed{f(2)=1;\ f^{-1}(1)=2;\ f^{-1}(f(2))=2}

Step-by-step explanation:

We have:

f(x)=\dfrac{1}{2}x and f^{-1}(x)=2x

f(2) → put x = 2 to the equation of a function f(x):

f(2)=\dfrac{1}{2}(2)=1

f⁻¹(1) → put x = 1 to the equation of a function f⁻¹(x):

f^{-1}(1)=2(1)=2

f⁻¹(f(2)) → put f(2) = 2 to the equation of a function f⁻¹(x):

f^{-1}(f(2))=f^{-1}(1)=2

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The regular price of a watch is $32.25. During a sale, the watch was marked 16% off. What was the price of the watch during the
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Answer:

$ 27.09

Step-by-step explanation:

Given,

The regular price of the watch = $ 32.25,

The marked off percentage or discount percentage, in the sale = 16%,

So, the amount of marked off = 16% of regular price

= 16% of 32.25

= 0.16 × 32.25

= $ 5.16

Hence, the the price of the watch during the sale = Regular price - marked off

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= $ 27.09

Last option is correct.

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3 years ago
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7 0
3 years ago
Please help Need help
Anettt [7]
This problem can be readily solved if we are familiar with the point-slope form of straight lines:
y-y0=m(x-x0) ...................................(1)
where 
m=slope of line
(x0,y0) is a point through which the line passes.

We know that the line passes through A(3,-6), B(1,2)

All options have a slope of -4, so that should not be a problem.  In fact, if we check the slope=(yb-ya)/(xb-xa), we do find that the slope m=-4.

So we can check which line passes through which point:

a. y+6=-4(x-3)
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b. y-1=-4(x-2) means line passes through (2,1), which is neither A nor B
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c. y=-4x+6  subtract 2 from both sides (to make the y-coordinate 2)
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d. y-2=-4(x-1)
   this is the same as the previous equation, so it passes through B(1,2), 
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Answer: the equation y-1=-4(x-2) does NOT pass through both A and B.
   
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