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MA_775_DIABLO [31]
3 years ago
6

(30 points) Please, if anyone can give me the answers to my Algebra 1b (semester two) cumulative exam, I'd be forever greatful e

ven if it's a link to a book or website anything helps!
Mathematics
2 answers:
OlgaM077 [116]3 years ago
8 0
I'd be glad to help!
Here is a Quizlet review page that may help:
https://quizlet.com/subject/semester-2-exam-review-algebra/
gayaneshka [121]3 years ago
3 0
I can answer individual questions, but i don't know any place where you can get all the answers
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I WILL GIVE BRAINLIEST TO WHOEVER GETS IT RIGHT.
zhenek [66]

Answer:

(5/6)

Step-by-step explanation:

Bc (2/3)=0.666666666667....

(2/15)*(4/5) doesn't make 0.666666666667

(4/5)*(5/6)= 0.666666666667

8 0
3 years ago
#8 HELP IM STUCK ON THIS
jeka57 [31]

Answer:

12 ft

Step-by-step explanation:

for the model is 1 and the actual is 5

conversion yards to feet

3 feet = 1 yard

20 * 3 = 60

60/5 = 12

your answers 12 ft

hope this helps:)

4 0
2 years ago
Sara buys 3 of the same type of dress, but in different colors. If she spends a total of $80.34, how much does each dress cost?
Musya8 [376]

Answer:

80.34 / 3 = 26.78


5 0
3 years ago
Read 2 more answers
Someone help me please and thank you!! ASAP :(
pantera1 [17]
<h3>Answer: Choice D) </h3>

Work Shown:

(f+g)(x) = f(x)+g(x)\\\\(f+g)(x) = \frac{x-23}{x^2+9x-36}+\frac{1}{x+12}\\\\(f+g)(x) = \frac{x-23}{(x+12)(x-3)}+\frac{1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+x-3}{x^2+9x-36}\\\\(f+g)(x) = \frac{2x-26}{x^2+9x-36}\\\\

We must require that x \ne -12 and x \ne 3 to avoid having 0 in the denominator. This is why choice D is the answer.

3 0
3 years ago
Using the diagram above,what is the m
makkiz [27]
I’m pretty sure the angle in 53 degrees
4 0
3 years ago
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