The answers is 30 km.....
1-First let’s list the numbers between 210 to 220, except the even ones since they’re a multiple of 2:
211; 213; 215; 217; 219
Let’s remove 213, and 219 because they’re multiples of 3 (2+1+3=6; 2+1+9=12), 215 is multiple of 5, so let’s remove it.
That leave’s is with 211, and 217.
We can remove 217, because it’s a multiple of 7, leaving us with 211.
2- It’s deductive reasoning, because you started with a more general idea.
3- {-7, -6, -5, -4, -3, -2, -1, 0, 1}
4- {x e R, x>=-2}
5-{-1, 0, 1}
6- {x∣-4≤ x ≤6}
7- [-20, ♾ )
8- On a number line, make a circle around -1, and continue the line to minus infinity.
9- On a number line, make a circle on -3, and continue to minus infinity. Make a ring on 0, and continue to infinity.
Since each term contains x, x= 0 is one answer Also as x^2 is a factor it has duplicity 2.
Factoring:-
x^2 (x^2 - 4x + 3) = 0
x^2( x - 3)(x - 1) = 0
so x = 3 and x = 1 are also zeros
Answer:- x = 0 (duplicity 2), x = 1 and x = 3.
Answer:
$5.35.
Step-by-step explanation:
The number of checks written after the first 10 = 24 - 10 = 14.
The fees for these checks = 14 * 0.10
= $1.40.
So his fees for March are 3.95 + 1.40
= $5.35.
C. they might miss realising that the first 10 checks are free.
Remark
Remove the brackets. Then solve as a normal inequality.
Solution
4(x - 3) - 2(x - 1) > 0
4x - 12 - 2x + 2 > 0 Combine like terms on the left
4x - 2x - 12 + 2 > 0
2x - 10 > 0 Add 10 to both sides
2x > 10 Divide by 2
x > 10/2
x > 5
Answer: B
Discussion
C and D are both true but these questions always assume that you are going to pick the lowest value that will allow the inequality to be true. x> 7 and x>14 will be included in x>5
