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Reika [66]
3 years ago
9

While attempting to score a goal, a player from the opposing team accidentally kicked Vance in the shin, causing an injury. What

is one way that Vance might have been able to prevent this injury?
Physics
2 answers:
hjlf3 years ago
7 0

Answer:

Explanation:

The shin bone is the tibia. It is located in the lower leg bone. It is larger then it's neighboring bone that is fibula. It supports the weight of the human body. It provides stability while standing. It is sensitive to fracture. Therefore, it is advice to wear the leg guard or shin guard to protect oneself from injury.

Therefore, Vance should wear leg guard or shin guard to prevent injury.

sergiy2304 [10]3 years ago
4 0
To prevent this injury, Vance could have protected his shins using a shin guard. Hope this helps! :)
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Answer: Hang out with your friends, go outside, eat some food, or going to the bathroom

You didn't specify enough for me to understand clearly so if this is not your answer then I cannot help you.

8 0
3 years ago
Which one is more important in science, qualitative or quantitative
Sergeeva-Olga [200]

Answer:

quantitative

Explanation: quantitative research is better for scientist.

5 0
3 years ago
What is the percentage by weight of a solution prepared by dissolving 10 g of NaCl in 100 g of H2O?
kirill [66]

Answer:

10

Explanation:

5 0
3 years ago
A traveling electromagnetic wave in a vacuum has an electric field amplitude of 72.7 V/m. 72.7 V/m. Calculate the intensity S S
Yakvenalex [24]

Answer:

a) 7.02 W/m²

b) 1.53 J

Explanation:

Given

Amplitude of the electric wave, = 72.7 V/m

Area of flow, A = 0.0211 m²

Time taken, t = 10.3 s

To calculate the Intensity, S. We use the formula

I = E(rms)² / (cμ), where

E(rms) = E / √2 = 72.7 / √2

E(rms) = 72.7 / 1.4142

E(rms) = 51.41

c = 2.99*10^8

μ = 1.26*10^-6

I = 51.41² / [(2.99*10^8) (1.26 x 10^-6)]

I = 2642.99 / 376.74

I = 7.02 W/m²

U = energy = IAt

U = (7.02) * (0.0211) (10.3) J = 1.53 J

3 0
3 years ago
Light is incident from air on the surface of a glass slab, which has an index of refraction of 2.5 In the air the light beam mak
djverab [1.8K]

Answer:

13.26°

Explanation:

Using Snell's law as:

n_i\times {sin\theta_i}={n_r}\times{sin\theta_r}

Where,  

{\theta_i}  is the angle of incidence  ( 35.0° )

{\theta_r} is the angle of refraction  ( ? )

{n_r} is the refractive index of the refraction medium  (glass, n=2.5)

{n_i} is the refractive index of the incidence medium (air, n=1)

Hence,  

1\times {sin35.0^0}={2.5}\times{sin\theta_r}

Angle of refraction= sin⁻¹ 0.2294 = 13.26°.

<u>13.26° is the angle of the beam with the normal in the glass.</u>

3 0
4 years ago
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