May u help me dind the answer for this problem please

Mathematics

1 answer:

kati45 [8]3 years ago

5 0

Answer:

The "shape" would be 784 Sq. Ft.

Step-by-step explanation:

Firstly, you need to find the area of the bottom "rectangle" by multiplying 20 by 14 to get 280 Sq. Ft. You then add 14 and 7 to get the length of the bottom of the upper "rectangle" to get 21. Now you continue in the steps of the bottom to multiply 24 by 21 to get 504 Sq. Ft. In the end, you add them together to get the total area to be 784 Sq. Ft.

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What is the sum of 2/11’ 2/7’ and 1/11’?

pav-90 [236]

Solution

To solve this addition of fractions we are gonna apply the fraction rule which is;

a/c + b/c = (a + b)/c

2/11 + 1/11 = (2 + 1)/11

= (2 + 1)/11 + 2/7

Now add the numerators 2 + 1

= (2 + 1)/11 + 2/7

= 3/11 + 2/7

Now we find the least common multiple

The least common multiple of 11 and 7 is 77.

But before that we cross multiply the numerators.

3 * 7 = 21
2 * 11 = 22

Now the ajustes fraction is;

21/77 + 22/77

Apply the fraction rule which is;

a/c + b/c = (a + b)/c

= (21 + 22)/77

Now we add the numerators.

43/77

Therefore the answer in fraction is 43/77 and in decimal form it is 0.55841

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2 years ago

Find the area. Round to the nearest tenth.

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Answer:

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Step-by-step explanation:

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3 years ago

Evaluate cos(sin^-1(4/5)

PSYCHO15rus [73]

Step-by-step explanation:

$Let \: \: \theta = \sin^{ - 1} (\frac{4}{5}) \\ \\ \therefore \: \sin\theta = \frac{4}{5} \\ \\ \because \: { \cos}^{2} \theta =1 - { \sin}^{2} \theta \\ \\ \therefore \: { \cos}^{2} \theta = 1 - (\frac{4}{5} )^{2} \\ \\ = 1 - \frac{16}{25} \\ \\ = \frac{25 - 16}{25} \\ \\ = \frac{9}{25} \\ \\ \therefore \:{ \cos}\theta = \pm \: \frac{3}{5} \\ \\ \because \: \theta \: lie \: in \: the \: first \: quadrant \\ \\ \therefore \: { \cos}\theta = \: \frac{3}{5} \\ \\ \implies \theta = { \cos}^{ -1 } \: \frac{3}{5}\\\\\implies \theta = { \cos}^{ -1 } \: \frac{3}{5}= { \sin}^{ -1 } \: \frac{4}{5} \\ \\ \therefore \: \cos( \ {sin}^{ - 1} \frac{4}{5} ) \\ \\ = \cos( \ {cos}^{ - 1} \frac{3}{5} ) \\\\ = \frac{3}{5} \\ \\ \purple{ \boxed{\therefore \: \cos( \ {sin}^{ - 1} \frac{4}{5} ) = \frac{3}{5}}}$