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3 years ago

A letter of the alphabet is chosen at random. Find the probability that the letter selected is a vowel.

Mathematics

1 answer:

Ann [662]3 years ago

5 0

Answer:

<u>The correct answer is B. 5/26.</u>

Step-by-step explanation:

Let's recall what is the formula of the probability of any event:

Probability of an event= Number of favorable outcome/Total number of favorable outcomes

Then, replacing with the values of our question:

Probability of selecting a vowel = Number of vowels/Total number of letters of the alphabet

Probability of selecting a vowel = 5/26

<u>The correct answer is B. 5/26.</u>

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Yuliya22 [10]

6p+10p+15-9

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2 years ago

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malfutka [58]

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1 year ago

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Calls to a customer service center last on average 2.8 minutes with a standard deviation of 1.4 minutes. An operator in the call

Natali5045456 [20]

Answer:

The expected total amount of time the operator will spend on the calls each day is of 210 minutes.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

n-values of normal variable:

Suppose we have n values from a normally distributed variable. The mean of the sum of all the instances is $M = n\mu$ and the standard deviation is $s = \sigma\sqrt{n}$

Calls to a customer service center last on average 2.8 minutes.

This means that $\mu = 2.8$

75 calls each day.

This means that $n = 75$

What is the expected total amount of time in minutes the operator will spend on the calls each day

This is M, so:

$M = n\mu = 75*2.8 = 210$

The expected total amount of time the operator will spend on the calls each day is of 210 minutes.

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2 years ago

Masteriza [31]

The money altogether is 8.00$

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3 years ago

f the centripetal and thus frictional force between the tires and the roadbed of a car moving in a circular path were reduced, w

LUCKY_DIMON [66]

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This principle is applied on racing tracks, where the road is inclined away from the circle to give the car an extra restoring force to overcome the centripetal force.

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