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2 years ago

Find a close estimate for: √18

Mathematics

2 answers:

sashaice [31]2 years ago

6 0

The square root for 18 is 4.242.... , not sure how you want it estimated

aev [14]2 years ago

4 0

Another way to estimate sqrt(18) is to understand that

sqrt(18)

=sqrt(9)sqrt(2)

=3sqrt(2)

=3*1.414

=4.242

Note: estimate for sqrt(2) can be by common usage, or the fact that 14*14=196.

memorizing a few square-roots is an advantage in these situations:

sqrt(2)=1.41421356

sqrt(3)=1.7320508

sqrt(5)=2.2360680

etc.

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4 = 3x -x-4<br> I need steps to how to do this

vesna_86 [32]

Step-by-step explanation:

so first you combine like terms , 3x-x-4=4 turns into 4x-4=4 then u add 4 to both sides [inverse operations]

4x-4=4

+4 +4

--------------

4x= 8

----------

4. 4

×=2

then u use inverse operations. agian and divide 4 into 8 and you get 2 !! x = 2

4 0

3 years ago

Read 2 more answers

Please solve for the hypotenuse of a right triangle having legs 6 and 8. *

Arturiano [62]

Answer:

Step-by-step explanation:

6²+8²

=100

√100

=10

6 0

3 years ago

Work out the length of the following rectangles

tiny-mole [99]

(a) a = 10.9 cm

(b) b = 20.78 cm

(c) c = 4.06 cm

<u>Explanation:</u>

(a)

height, h = 5cm

Hypotenuse, H = 12cm

Base, a = ?

Using pythagoras theorm:

(H)² = (h)² + (a)²

(12)² = (5)² + (a)²

119 = a²

a = 10.9 cm

(b)

Hypotenuse, H = 24 cm

Base, a = 12 cm

Height, b = ?

Using pythagoras theorm:

(H)² = (b)² + (a)²

(24)² = (b)² + (12)²

432 = b²

b = 20.78 cm

(c)

height, h = 4 cm

Hypotenuse, H = 5.7 cm

Base, c = ?

Using pythagoras theorm:

(H)² = (h)² + (c)²

(5.7)² = (4)² + (c)²

16.49 = c²

c = 4.06 cm

8 0

3 years ago

What is the midpoint of the segment show below?

slega [8]

B is the answer because if u subtact both x and y

3 0

3 years ago

Read 2 more answers

Given vectors A (2,-1,5), B (4,3,-2) & C (5,4,0), find:?

MrRissso [65]

A) 4a - 3b + 2c

4(2, -1, 5) - 3(4, 3 , -2) + 2(5, 4, 0) = (8, -4, 20) - (12, 9, - 6) + (10, 8, 0) =

= (8 - 12 + 10 , -4 - 9 + 8 , 20 + 6 + 0) = (6, - 5, 26)

Answer: (6, - 5, 26)

b) magnitude of vector b

$\sqrt{4^2+3^2+(-2)^2} = \sqrt{16+9+4} = \sqrt{29} ~ 5.4$

c) vector of length 7 parallel to vector c

=> m(5,4,0) = (5m,4m,0)

=> $\sqrt{(5m)^2+(4m)^2+0}= \sqrt{25m^2+16m^2}= \sqrt{41m^2}=m \sqrt{41}=7$

=> m = 7 / √41 ≈ 1.093

=> 1.093 (5, 4, 0) = (5.465 , 4.372, 0)

Answer: (5.465 , 4.372 , 0)

7 0

3 years ago