Answer:
yes
Step-by-step explanation:
Looks like your function is

Rewrite it as

Recall that for
, we have

If we replace
with
, we get

By the ratio test, the series converges if

Solving for
gives the interval of convergence,

We can confirm that the interval is open by checking for convergence at the endpoints; we'd find that the resulting series diverge.
We know the distance formula is

9)
Here A( -4,2) and B(1,4)
So length of AB
= 
Also C(2,1)
Length of BC
= 
So we can see that length of AB is not equal to length of BC
11.
Now AB = 
Also C(2,-1) & D(4,4)
Length of CD
= 
Yes AB = CD
Answer:it’s the third one
Step-by-step explanation: