Answer:Given that the graph shows tha the functión at x = 0 is below the y-axis, the constant term of the function has to be negative. This leaves us two possibilities:
y = 8x^2 + 2x - 5 and y = 2x^2 + 8x - 5
To try to discard one of them, let us use the vertex, which is at x = -2.
With y = 8x^2 + 2x - 5, you get y = 8(-2)^2 + 2(-2) - 5 = 32 - 4 - 5 = 23 , which is not the y-coordinate of the vertex of the curve of the graph.
Test the other equation, y = 2x^2 + 8x - 5 = 2(-2)^2 + 8(-2) - 5 = 8 - 16 - 5 = -13, which is exactly the y-coordinate of the function graphed.
Step-by-step explanation:
Answer:
good you got the answer
Step-by-step explanation:
To do this you must combine like terms as follows.
7x + 6x = 13x
7 - 9 = -2
Combine these together and you will get the following.
13 - 2 or -2 +13
For this case, what you should do is use any computational tool and graph the data in the table. For example, I used excel.
In the x axis we have Starting temperature and in the axis of the y we have Ending temperature.
You can see how the diagram varies almost linearly.