Answer:
the bottom right
Step-by-step explanation:
Answer:
x = -2
Step-by-step explanation:
Solve for x:
(2 (3 x - 4))/5 = -4
Multiply both sides of (2 (3 x - 4))/5 = -4 by 5/2:
(5×2 (3 x - 4))/(2×5) = -4×5/2
5/2×2/5 = (5×2)/(2×5):
(5×2)/(2×5) (3 x - 4) = -4×5/2
5/2 (-4) = (5 (-4))/2:
(5×2 (3 x - 4))/(2×5) = (-4×5)/2
(5×2 (3 x - 4))/(2×5) = (2×5)/(2×5)×(3 x - 4) = 3 x - 4:
3 x - 4 = (-4×5)/2
(-4)/2 = (2 (-2))/2 = -2:
3 x - 4 = 5×-2
5 (-2) = -10:
3 x - 4 = -10
Add 4 to both sides:
3 x + (4 - 4) = 4 - 10
4 - 4 = 0:
3 x = 4 - 10
4 - 10 = -6:
3 x = -6
Divide both sides of 3 x = -6 by 3:
(3 x)/3 = (-6)/3
3/3 = 1:
x = (-6)/3
The gcd of -6 and 3 is 3, so (-6)/3 = (3 (-2))/(3×1) = 3/3×-2 = -2:
Answer: x = -2
Answer:
y=6^x-2
Step-by-step explanation:
Start with the parent function, a^x. The graph looks like it has been translated b units down, so our function is a^x+b. Now at x=0, y=-2. So b=-2. Next at x=1, y=3. 3=a^(1)-2, a=6. y=6^x-2 is the equation
Answer:
23%
Step-by-step explanation:
There are 4 male and 3 female freshmen. Thus the total number of freshmen is 7.
On the other hand, we have 14 male students and 16 female students. Thus the total number of students is 30.
If a student is selected at random, the probability that the student is a freshman is;
( 7/30) * 100 = 23.33%
Answer:
- 35 5-lb weights
- 25 3-lb weights
Step-by-step explanation:
Let t and f represent the numbers of three- and five-pound weights. The problem statement tells us ...
f + t = 60
f - t = 10
Adding these two equations, we get ...
(f +t) +(f -t) = (60) +(10)
2f = 70 . . . . . eliminate parentheses
f = 35 . . . . . . divide by 2
She has 35 5-lb weights, and 25 3-lb weights.
