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solmaris [256]
3 years ago
15

Pls help me with this question

Mathematics
1 answer:
choli [55]3 years ago
8 0
$142.60 for all three employees
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The answer would be (8pi +12) in^2
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3 years ago
How can you prove:<br><br> secθ = cscθtanθ
zavuch27 [327]

\sec \theta=\csc \theta\tan \theta\\\\ \dfrac{1}{\cos \theta}=\dfrac{1}{\sin \theta}\cdot\dfrac{\sin \theta}{\cos \theta}\\\\ \dfrac{1}{\cos \theta}=\dfrac{1}{\cos \theta}

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3 years ago
If given the equation y = 3(x + 5)2 - 4, what is the vertex of the parabola
Vlada [557]

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4 0
3 years ago
A report states that the mean yearly salary offer for students graduating with a degree in accounting is $48,734. Suppose that a
DENIUS [597]

Solution :

To claim to be tested is whether "the mean salary is higher than 48,734".

i.e. μ > 48,734

Therefore the null and the alternative hypothesis are

$H_0 : \mu = 48,734$

and $H_1 : \mu > 48,734$

Here, n = 50

$\bar x = 49,830$

s = 3600

We take , α = 0.05

The test statistics t is given by

$t=\frac{\bar x - \mu}{\frac{s}{\sqrt n}}$

$t=\frac{49,830 - 48,734}{\frac{3600}{\sqrt 50}}$

t = 2.15

Now the ">" sign in the $H_1$ sign indicates that the right tailed test

Now degree of freedom, df = n - 1

                                              = 50 - 1

                                              = 49

Therefore, the p value = 0.02

The observed p value is less than α = 0.05, therefore we reject $H_0$. Hence the mean salary that the accounting graduates are offered from the university is more than the average salary of 48,734 dollar.

3 0
3 years ago
Ke=(1)/(2)mv^(2)<br> solve for m
slava [35]

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

m=\frac{2Ke}{v\\^{2} }

8 0
3 years ago
Read 2 more answers
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