A parabola is an approximately U-shaped, mirror-symmetrical plane curve in mathematics. It corresponds to a number of seemingly unrelated mathematical descriptions, all of which can be shown to define the same curves. A parabola can be described using a point and a line.
A parabola equation is what is it?
A parabola's general equation is written as y = a(x - h)2 + k or x = a(y - k)2 + h.
To determine the equation of a parabola, we can utilize the vertex form. Assuming we can read the coordinates (h,k) from the graph, the aim is to utilize the coordinates of its vertex (maximum point, or minimum point), to formulate its equation in the form y=a(xh)2+k, and then to determine the value of the coefficient a.
To learn more about Parabola refer to:
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When it will hit the ground then height is 0
<span>h(t)=-16^2+250
-16^2+250=0
16t^2=250
t^2=250/16
t=3.95 seconds
i hope this is right</span>
Answer:
Part 1) The area of the figure is 
Part 2) The perimeter of the figure is 
Step-by-step explanation:
Part 1) Find the area of the figure
we know that
The area of the figure is equal to the area of three squares
so
![A=3[4^2]=48\ cm^2](https://tex.z-dn.net/?f=A%3D3%5B4%5E2%5D%3D48%5C%20cm%5E2)
Part 2) Find the perimeter of the figure
we know that
The perimeter of the figure is equal to two times the length side of the square, plus the circumference of six semicircles ( or the circumference of three circles)
Remember that
The circumference of a circle is equal to
where
D is the diameter of the circle
In this problem
so
![P=2(4)+3[\pi(4)]=(8+12\pi)\ cm](https://tex.z-dn.net/?f=P%3D2%284%29%2B3%5B%5Cpi%284%29%5D%3D%288%2B12%5Cpi%29%5C%20cm)
simplify
Answer:
Hello! answer: 2
Step-by-step explanation:
The mode is just the number shown the most in the set of numbers so 2 is the mode because 2 is shown the most Hope that helps!
The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
</span>
Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
