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Kruka [31]
3 years ago
10

Question 1 (1 point)

Computers and Technology
2 answers:
faltersainse [42]3 years ago
8 0

Answer:

The internet is completely dangerous.

Explanation:

The answer is false.

timama [110]3 years ago
7 0

Answer:

false

Explanation:

people get bullied and theres bad people on social medias

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professor190 [17]
They have the same  vertical resolution. I can suggest you to watch the video in youtube .<span>https://www.youtube.com/watch?v=uluEEGBHyUE</span>
7 0
3 years ago
Oliva was a sophomore thriving in college when her father was laid off from his job. Even with financial aid, the family could n
Zielflug [23.3K]

Answer:

Linked Lives

Explanation:

Linked-lives is a popular preposition, the idea is that people who are related to each like father-child or mother-child relationship have similar influencing trajetories of development that cuts across their lives.

6 0
4 years ago
Create an array to hold the rainfall values. Create a 2nd parallel array (as a constant) to hold the abbreviated names of the mo
Zarrin [17]

Answer:

#include <stdio.h>

int main()

{

//variable declaration

int low, high;

float lowRain, highRain, total, avg;

 

//array declaration

float rainfall[13];

char monthName[13][10] = {"", "Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"};

//get user input

for(int i=1; i<=12; i++)

{

printf("Enter the rainfall (in inches) for %s: ", monthName[i]);

scanf("%f", &rainfall[i]);

}

 

//display the monthly rainfall

printf("\nThe rainfall that was entered was:\n");

for(int i = 1; i<=6; i++)

printf("%s ", monthName[i]);

printf("\n");

for(int i = 1; i<=6; i++)

printf("%.1f ", rainfall[i]);

printf("\n");

for(int i = 7; i<=12; i++)

printf("%s ", monthName[i]);

printf("\n");

for(int i = 7; i<=12; i++)

printf("%.1f ", rainfall[i]);

 

//variable initialization

low = 1;

high = 1;

lowRain = rainfall[1];

highRain = rainfall[1];

total = 0;

 

//calculate the lowest, highest and averaage rainfall

for(int i=1; i<=12; i++)

{

if(lowRain>rainfall[i])

{

lowRain = rainfall[i];

low = i;

}

if(highRain<rainfall[i])

{

highRain = rainfall[i];

high = i;

}

total = total + rainfall[i];

}

 

avg = total / 12;

 

//display the result

printf("\n\nThe total rain that fell was %.1f inches", total);

printf("\nThe average monthly rainfall was %.1f inches.", avg);

printf("\nThe lowest monthly rainfall was %.1f inches in %s.", rainfall[low], monthName[low]);

printf("\nThe highest monthly rainfall was %.1f inches in %s.", rainfall[high], monthName[high]);

return 0;

}

4 0
4 years ago
An online survey is an effective way for an administrative professional to gather information. True False
Strike441 [17]

Answer:

True is the correct answer for the above question.

Explanation:

  • An online survey is done with the help of social sites that connects many people in conversation from all over the world. So to do an effective survey, it is best to choose the online medium.
  • The administrative professional is a professional, who works to do administrative tasks like managing the organization.
  • The above question-statement says that the online survey is the best survey, which is the correct statement, which is described above. Hence the answer is true for the above question.
7 0
3 years ago
Write a recursive method called repeat that accepts a string s and an integer n as parameters and that returns s concatenated to
svp [43]

Answer:

public static String repeat(String text, int repeatCount) {

   if(repeatCount < 0) {

       throw new IllegalArgumentException("repeat count should be either 0 or a positive value");

   }

   if(repeatCount == 0) {

       return "";

   } else {

       return text + repeat(text, repeatCount-1);

   }

}

Explanation:

Here repeatCount is an int value.

at first we will check if repeatCount is non negative number and if it is code will throw exception.

If the value is 0 then we will return ""

If the value is >0 then recursive function is called again untill the repeatCount value is 0.

6 0
3 years ago
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