Question

Need help with 7A plz

Answer 1

A) area of square = base*height/////Triangle= 0.5*base*height

=(a^1/3*b^3/4)*(a^2/3*b^1/2)+(1/2*a^1/3*b^3/4*a^2/3*b^1/4)
=(a^1*b^5/4)+(1/2*a^1*b^1)
=(a*b^5/4)+(1/2*a*b)

B) a^2+b^2=c^2 (pythagorean theorem)
   ((27^2/3)*(16^1/4))^2 +  (27^1/3)*(16^3/4)   
     (9*2=(18^2))=324 +  (3*8= 24^2)= 576
      324+576= 900
     (900)^1/2= 30
hypotenuse= 30

C)( a^2/3*b^1/2)= 36*2(two sides)= 72
    (a^1/3b^3/4)=24
    (a^2/3*b^1/4)= 18
  72+24+18+30(hypotenuse)= 144=perimeter