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NNADVOKAT [17]
2 years ago
7

What form is 4.6 X 10' written in?

Mathematics
1 answer:
ziro4ka [17]2 years ago
4 0

Answer: Standard Form

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I think the answer c
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The number obtained on rationalizing the denominator of 1/(√7--2) is
Slav-nsk [51]

\frac{1}{ \sqrt{7}  -(- 2)}  \\ rationalizing \:  \:  \: the \:  \:  \: denominator \:  \:  \: we \:  \:  \: have \\  =  \frac{1}{ \sqrt{7} + 2 }  \times  \frac{ \sqrt{7}  - 2}{ \sqrt{7}  - 2}  \\  =  \frac{ \sqrt{7}  - 2}{ {( \sqrt{7} )}^{2} -  {(2)}^{2}  }  \\  =  \frac{ \sqrt{7} - 2 }{7 - 4}  \\  =  \frac{ \sqrt{7}   - 2}{3}

Hope you could get an idea from here.

Doubt clarification - use comment section.

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2 years ago
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Solve for a r=x(a+b)<br><br><br> Solve for x x/2=-7
Anastaziya [24]

Answer:

a = (r/x) -b

x = -14

Step-by-step explanation:

r=x(a+b)

Divide each side by x

r/x = a+b

Subtract b

r/x  -b = a

x/2=-7

Multiply each side by 2

x/2*2 = -7*2

x = -14

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Suppose a particular type of cancer has a 0.9% incidence rate. Let D be the event that a person has this type of cancer, therefo
natita [175]

Answer:

There is a 12.13% probability that the person actually does have cancer.

Step-by-step explanation:

We have these following probabilities.

A 0.9% probability of a person having cancer

A 99.1% probability of a person not having cancer.

If a person has cancer, she has a 91% probability of being diagnosticated.

If a person does not have cancer, she has a 6% probability of being diagnosticated.

The question can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem we have the following question

What is the probability that the person has cancer, given that she was diagnosticated?

So

P(B) is the probability of the person having cancer, so P(B) = 0.009

P(A/B) is the probability that the person being diagnosticated, given that she has cancer. So P(A/B) = 0.91

P(A) is the probability of the person being diagnosticated. If she has cancer, there is a 91% probability that she was diagnosticard. There is also a 6% probability of a person without cancer being diagnosticated. So

P(A) = 0.009*0.91 + 0.06*0.991 = 0.06765

What is the probability that the person actually does have cancer?

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.91*0.009}{0.0675} = 0.1213

There is a 12.13% probability that the person actually does have cancer.

3 0
3 years ago
In a coffee shop, the average drink is currently $4.50 while the average pastry is $2.25. You've made a total of $5,250 today. W
Kamila [148]

Answer:

4.50x+2.25y=5,250  where x denotes number of drinks and y denotes number of pastries.

Step-by-step explanation:

Let x denotes number of drinks and y denotes number of pastries.

Cost of the average drink = $4.50

Cost of the average pastry = $2.25

Total amount = $5,250

Therefore,

4.50x+2.25y=5,250

6 0
3 years ago
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