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ycow [4]
3 years ago
9

Does anyone know how to solve this?

Mathematics
1 answer:
Lilit [14]3 years ago
4 0

The pattern is that the numbers in the right-most and left-most squares of the diamond add to the bottom square and multiply to reach the number in the top square.


For example, in the first given example, we see that the numbers 5 and 2 add to the number 7 in the bottom square and multiply to the number 10 in the top square.


Another example is how the numbers 2 and 3 in the left-most and right-most squares add up to the number 5 in the bottom square and multiply to the number 6 in the top square.


Using this information, we can solve the five problems on the bottom of the paper.


a) We are given the numbers 3 and 4 in the left-most and right-most squares. We must figure out what they add to and what they multiply to:

3 + 4 = 7

3 x 4 = 12

Using this, we can fill in the top square with the number 12 and the bottom square with the number 7.


b) We are given the numbers -2 and -3 in the left-most and right-most squares, which again means that we must figure out what the numbers add and multiply to.

(-2) + (-3) = -5

(-2) x (-3) = 6

Using this, we can fill the top square in with the number 6 and the bottom square with the number -5.


c) This time, we are given the numbers which we typically find by adding and multiplying. We will have to use trial and error to find the numbers in the left-most and right-most squares.


We know that 12 has the positive factors of (1, 12), (2,6), and (3,4). Using trial and error we can figure out that 3 and 4 are the numbers that go in the left-most and right-most squares.


d) This time, we are given the number we find by multiplying and a number in the right-most square. First, we can find the number in the left-most square, which we will call x. We know that \frac{1}{2}x = 4, so we can find that x, or the number in the left-most square, is 8. Now we can find the bottom square, which is the sum of the two numbers in the left-most and right-most squares. This would be 8 + \frac{1}{2} = \frac{17}{2}. The number in the bottom square is \boxed{\frac{17}{2}}.


e) Similar to problem c, we are given the numbers in the top and bottom squares. We know that the positive factors of 8 are (1, 8) and (2, 4). However, none of these numbers add to -6, which means we must explore the negative factors of 8, which are (-1, -8), and (-2, -4). We can see that -2 and -4 add to -6. The numbers in the left-most and right-most squares are -2 and -4.

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kari74 [83]
Answer: B


a median of a triangle is a line segment joining a vertex to the midpoint of the opposite side, thus bisecting that side.



Hope this helps!
7 0
3 years ago
X/7=x+14 / 5<br> Solve for X
elixir [45]

Answer:

x/7=x+14 / 5

Solve for X

Step-by-step explanation:

x/7=x+14 / 5

Solve for X

6 0
3 years ago
A rhombus shaped fountain has diagonals that measure 8.4 meters and 10.2 meters. What is the area of the rhombus?
pantera1 [17]
The answer is 85.68 squared
6 0
3 years ago
Rachel and her friends are making necklaces out of beads and straws. They plan to use 12 beads and 5 straws for each necklace. T
bagirrra123 [75]

Answer:

225 necklaces.

Step-by-step explanation:

Assuming that they have the necessary amount of straws to match the beads then we can use the following simple equation to solve this problem.

t = b/12  ... where t is the total amount of necklaces and b is the number of beads you have

t = 2700 / 12

225 necklaces.

For 225 necklaces you would also need 1125 straws since each necklace requires 5 straws to be fully made. Therefore if you have this amount you should not run into any problems.

3 0
3 years ago
Can someone please help me with these? I'm giving 100 points so please.
Cerrena [4.2K]

Answer:

1. -2\frac{9}{12}

2. 10\frac{1}{8}

3. 3

4. -1 > x

Step-by-step explanation:

1.

-\frac{33}{12}  \\12 * 2 = 24\\33 - 24 = 9\\-2\frac{9}{12}

2.

10 \frac{1}{8} / \frac{3}{4} = 13\frac{1}{2} \\13\frac{1}{2} + \frac{1}{2} = 14

3. All share the factor of 3

4. Open circle is used for < (less than) or > (greater than). Shade to the right for > or ≥.

I hope this helps! May I please have brainliest? :)

8 0
2 years ago
Read 2 more answers
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