this can be solve using newtons heating of cooling
(Ts – T) =(Ts – To)*e^(-kt)
Where Ts is the ambient temperature
To is initial temperature
T is the temperature at time t
t is the time
k is constant
fisrt solve the constant k for the given first scenario
(99 – 36) = (99 – 46)*e(-5k)
K = -0.0346
Using k, solve T at t = 13 min
(99 – 46) = (99 – T)*e(-13*(-0.0346)
T = 58.82 degree F
Answer:
x = 12
Step-by-step explanation:
-3x+12=48
-12 -12
*subtract 12 from both sides
-3x = 36
-3x/3 = 36/3
*divide 3 from each sides
x = 12
