Question

One student from a high school will be selected at random. Let A be the event that the selected student is a student athlete, and let B be the event that the selected student drives to school. If P(A∩B)=0.08 and P(B|A)=0.25, what is the probability that the selected student will be a student athlete?

Answer 1

Answer:

0.32

Step-by-step explanation:

P(B|A) = P(A∩B) / P(A)

0.25 = 0.08 / P(A)

P(A) = 0.32

Answer 2

Answer:

The probability that the selected student will be a student athlete is 0.32.

Step-by-step explanation:

Given : One student from a high school will be selected at random. Let A be the event that the selected student is a student athlete, and let B be the event that the selected student drives to school.

If P(A∩B)=0.08 and P(B|A)=0.25

To find : What is the probability that the selected student will be a student athlete?

Solution :

One student from a high school will be selected at random and the selected student will be a student athlete i.e. $P(A)$

Using conditional probability,

$P(B|A) =\frac{P(A\cap B)}{P(A)}$

$0.25= \frac{0.08}{P(A)}$

$P(A)= \frac{0.08}{0.25}$

$P(A)=0.32$

Therefore, the probability that the selected student will be a student athlete is 0.32.