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inna [77]
3 years ago
11

What is the answer? 3rd time posting. Worth 15 points. Explain

Mathematics
2 answers:
Gekata [30.6K]3 years ago
4 0
KCC
7 units 7-4=3 (-9)-(-5)=
-9+5=(-4)
3+(-4)= 7
Troyanec [42]3 years ago
3 0
The answer would be 5
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Divide total pain by number of books.

296/8 = 37

He paid $37 per book

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Raj has 40% of his weekly paycheck automatically dispositive into his savings account this week $160 is dispositive into the acc
ella [17]

Answer:

  Raj can look on his pay stub to find the total is $400

Step-by-step explanation:

The relation between the deposit and the total pay is ...

  deposit = 0.40 × total pay

  total pay = deposit / 0.40 = 160/0.40 = 400

Raj was paid $400 this week.

7 0
3 years ago
An airline finds that 5% of the persons making reservations on a certain flight will not show up for the flight. If the airline
Greeley [361]

Answer:

0.5438 = 54.38% probability that a seat will be available for every person holding a reservation and planning to fly

Step-by-step explanation:

We use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 105, p = 1 - 0.05 = 0.95

I use p = 0.95 because i consider a success a person showing up to the flight. 5% probability that a person misses the flight, so 100-5 = 95% probability that a person shows up to the flight.

For the approximation:

\mu = E(X) = np = 105*0.95 = 99.75

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{105*0.95*0.05} = 2.23

What is the probability that a seat will be available for every person holding a reservation and planning to fly?

Probability of 100 or less people showing up, which is the pvalue of Z when X = 100. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{100 - 99.75}{2.23}

Z = 0.11

Z = 0.11 has a pvalue of 0.5438

0.5438 = 54.38% probability that a seat will be available for every person holding a reservation and planning to fly

4 0
2 years ago
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