For a triangle the area is given as:
Re-arrange / solve for 'h':
Substitute known values:
Compute:
Okay, here we have this:
Considering the provided expression, we are going to analize which exponential expression is equivalent, so we obtain the following:
As the property of the exponent of a multiplication says that it is equal to the product of each number raised to that power. We have this:
Finally we obtain that the correct answer is the option D.
1. Potential Energy = mgh
h = U_g / (mg) = 14 / (17 * 9.81) = <u>0.084 m above the ground.</u>
2. Kinetic Energy = 1/2 mv^2
m = 2K_e / (v^2) = <u>2.45 kg</u>
3. U_g = mgh = (1200)(9.81)(24) = <u>282528 J</u>
4. U_g = mgh = (478)(9.81)(150) = <u>703377 J</u>
5. U_g = mgh = (100)(9.81)(12.5) = <u>12262.5 J</u>
6. h = U_g / (mg) = 14 / (17 * 9.81) = <u>0.084 m above the ground.</u>
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7. m = U_g / (gh) = 1500 / (9.81 * 35) = <u>4.37 kg</u>
Given data in that table forms the 2x3 matrix shown below 2 7 6 5 4 5 a 3-point field goal is worth 3 points a normal field goal is worth 2 points a free throw is worth 1 points.
1) given function
y = - 2 ^ ( -x + 2) + 1
2) domain: domain is the set of the x-values for which the function is defined.
The exponential function is defined for all the real numbers, so the domain of the given function is all the real numbers.
3) x-intercept => y = 0
=> y = - 2 ^ ( -x + 2) + 1 = 0 => 2^ ( -x + 2) = 1
=> - x + 2 = 0 => x = 2
The x-intercept is x = 0
4) y-intercept => x = 0
=> y = - 2 ^ ( -x + 2) + 1= - 2 ^ ( 0 + 2) 1 = - (2)^(2) + 1 =- 4 + 1 = - 3
=> The y-intercept is - 3
5) limit when x -> negative infinite
Lim f(x) when x -> ∞ = - ∞
6) limit when x -> infinite
Lim f(x) when x - > infinite = 1
=> asymptote = y = 1
7) range is the set of values of the fucntion: y
Given that the function is strictly decreasing from -∞ to ∞, the range is from - ∞ to less than 1
Range (-∞,1)
