Answer:
46÷5=9.2
so the answer is 9 days
Step-by-step explanation:
Step-by-step explanation:
To get the inverse, swap the x- and y-variables, then solve for y. We should have the equation:
Solving for y:
because or
So on interchanging the variable, we get the equation:
6) Copy and complete each sequence below.A)1,3,6,10,___,____b)8,7,5,2,____,____c)1,4,9,16,____,_____d) What is the pattern for c
Free_Kalibri [48]
Answer:
A) 15,21
B) -2,-7
C) 25,36
D) These numbers are square roots of 1,2,3,4,....
Hope this will help:)
Answer:
Quotient: x+7
Remainder: -2
Step-by-step explanation:
Divide the terms (x² ÷ x =x)↓
(x² + 11x + 26) ÷ (x + 4) =x
Subtract x² + 4x (You have to the sign if each term)
(x² + 11x + 26) ÷ (x + 4) =x
-x² - 4x
-------------------
7x + 26
Divide the terms (7x ÷ x = 7)
x² + 11x + 26) ÷ (x + 4) =x + 7
Multiply the quotient by the dividend (x + 4) × 7 = 7x+28
(x² + 11x + 26) ÷ (x + 4) =x
-x² - 4x
-------------------
7x + 26
7x + 28
------------------
= -2 Remainder
Answer:
WU = (14√13)/13 ≈ 6.6564
Step-by-step explanation:
Call the incenter of ∆KWU point A. Call the center of circle ω2 point B.
Then ∠KWA has half the measure of arc WA. ∠AWU is congruent to ∠KWA, so also has half the arc measure. That is, ∠KWU has the same measure as arc WA and ∠KBW.
KB is a perpendicular bisector of chord WU, so ∆KWB is a right triangle, of which WU is twice the altitude to base KB.
The length of KB can be found several ways. One of them is to use the Pythagorean theorem:
KB² = KW² +WB² = 4² +6² = 52
KB = √52 = 2√13
The area of triangle KWB is ...
area ∆KWB = (1/2)KW·WB = (1/2)(4)(6) = 12 . . . . square units
Using KB as the base in the area calculation, we have ...
area ∆KWB = (1/2)(KB)(WU/2)
12 = KB·WU/4
WU = 48/KB = 48/(2√13) = 24/√13
WU = (24√13)/13 ≈ 6.6564