Jeremy says that 5.676677666777... is a rational number because it is decimal that goes on forever

if angle 1 and angle 2 are vertical angles, angle 2 and angle 3 are complementary angles and the measure of angle 3 is 56 degree

dimulka [17.4K]

Answer:

34º

Step-by-step explanation: so basically you know a complementary angle is 2 angles that make a straight line and a vertical angle crosses which means 2 angles are congruent to each other so I drew a line that bisected the angle by drawing a line that cut through the right angle and i extended a line down from the right angle so now I have a vertical angle and a complementary so from here I labeled each angle <1 <2 <3 If I know angle 3 is 56º then I know 56 plus __ equals 90º I then subtracted 56 from 90 and I got 34 and since I am trying to figure out what angle 1 is I know that angle 1 and 2 are vertical angles therefore I know they are congruent to each other so <1 = 34º

6 0

3 years ago

What is the mean of this data set 82,105,247,119,94,202

Kazeer [188]

To find the mean, add the numbers, and divide by the amount of numbers there is.

(82 + 105 + 247 + 119 + 94 + 202)/6

Simplify. Remember to follow PEMDAS. First, add

(849)/6

Next, divide by 6

849/6 = 141.5

141.5 should be your answer

hope this helps

6 0

3 years ago

Read 2 more answers

Please solve this question.

andre [41]

Answer:

x = - 2

y = 5

Step-by-step explanation:

Hi there !

2x + 9 = y

y = - 4x - 3

equality

2x + 9 = - 4x - 3

2x + 4x = - 9 - 3

6x = - 12

x = - 12 : 6

x = - 2

replace x = - 2

2(-2) + 9 = y

- 4 + 9 = y

y = 5

Good luck !

8 0

3 years ago

What statement describes the graph of x=4?

kherson [118]

Answer:

it is parallel to the y axis

3 0

3 years ago

Read 2 more answers

Scores on a test are normally distributed with a mean of 81.2 and a standard deviation of 3.6. What is the probability of a rand

Misha Larkins [42]

Answer:

The probability of a randomly selected student scoring in between 77.6 and 88.4 is 0.8185.

Solution:

Given, Scores on a test are normally distributed with a mean of 81.2

And a standard deviation of 3.6.

We have to find What is the probability of a randomly selected student scoring between 77.6 and 88.4?

For that we are going to subtract probability of getting more than 88.4 from probability of getting more than 77.6

Now probability of getting more than 88.4 = 1 - area of z – score of 88.4

$\mathrm{Now}, \mathrm{z}-\mathrm{score}=\frac{88.4-\mathrm{mean}}{\text {standard deviation}}=\frac{88.4-81.2}{3.6}=\frac{7.2}{3.6}=2$

So, probability of getting more than 88.4 = 1 – area of z- score(2)

= 1 – 0.9772 [using z table values]

= 0.0228.

Now probability of getting more than 77.6 = 1 - area of z – score of 77.6

$\mathrm{Now}, \mathrm{z}-\text { score }=\frac{77.6-\text { mean }}{\text { standard deviation }}=\frac{77.6-81.2}{3.6}=\frac{-3.6}{3.6}=-1$

So, probability of getting more than 77.6 = 1 – area of z- score(-1)

= 1 – 0.1587 [Using z table values]

= 0.8413

Now, probability of getting in between 77.6 and 88.4 = 0.8413 – 0.0228 = 0.8185

Hence, the probability of a randomly selected student getting in between 77.6 and 88.4 is 0.8185.

4 0

3 years ago