The answer would be 0

Reminder: when you see “-(-“ always think of plus sign “+.” (My teacher in middle school taught me that). So, -3+3 would be that the answer is 0.

4 0

3 years ago

If f(x) = 4x-x², find<br> square root f(3/2)

katrin [286]

Answer:

$\frac{\sqrt{15} }{2}$

Step-by-step explanation:

$\sqrt{f(\frac{3}{2} )$ , substitute $\frac{3}{2}$ to x

$f(\frac{3}{2} )=4(\frac{3}{2} )-(\frac{3}{2} )^2$ = $\frac{15}{4}$ or 3.75

$\sqrt{f(\frac{3}{2} )$ = $\sqrt{3.75}$ = $\frac{\sqrt{15} }{2}$

6 0

1 year ago

A physical fitness association is including the mile run in its secondary-school fitness test. The time for this event for boys

Luba_88 [7]

Answer:

$z=-1.28$

And if we solve for a we got

$a=470 -1.28*60=393.2$

So the value of height that separates the bottom 10% (Fastest 10%) of data from the top 90% is 393.2.

so if the time is 393.2 or lower a boy would earn a certificate of recognition from the fitness association

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the time for this event of a population, and for this case we know the distribution for X is given by:

$X \sim N(470,60)$

Where $\mu=470$ and $\sigma=60$

NOTE: For this case the fastest 10% is on the lower tail of the distribution

For this part we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.9$ (a)

$P(X$ (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.1 of the area on the left and 0.9 of the area on the right it's z=-1.28. On this case P(Z<-1.28)=0.1 and P(z>-1.28)=0.9

If we use condition (b) from previous we have this:

$P(X$

$P(z$

But we know which value of z satisfy the previous equation so then we can do this: