\left[x \right] = \left[ \frac{5\,y}{158}+\frac{6\,z}{79}\right][x]=[1585y+796z]
Solution -
In order to convert a binary number to hexadecimal ,we need to chunk the binary number into groups of 4 digits, adding 0 if necessary.
As the given number number is a 16 digit binary number, so when chunk in 4 digit groups, it will form 4 groups. Each group will represent a single digit in hexadecimal code.
So, a 16-digit binary pattern converts to a 4 digit hexadecimal value.
The is the answer on my paper:
Answer:
I am so sorry
Step-by-step explanation:
I dont really know what it is but I think it is 21.98 you do 7 times 3.14