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3 years ago

If the approximate height of this right prism with triangular bases is 2.6 centimeters, what is its approximate surface area?

Mathematics

1 answer:

Shkiper50 [21]3 years ago

3 0

I think it is 66.3cm but I’m not sure

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Choose a variable to represent one of the unknowns. Express the remaining unknowns in terms of the variable you chose in step 1.

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Let's just choose "x" as our variable for the length of a side of the triangle.

Two sides of a triangle are equal in length and double the length of the shortest side.

A triangle has 3 sides. Make the smallest side x then the two equal sides that are double the smallest side are both equal to 2x

The perimeter of the triangle is 35 inches. Perimeter is the sum of all sides.

x + 2x + 2x = 35

5x = 35

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2 years ago

Which values are solutions to the inequality below? Check all that apply.

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Answer:

Step-by-step explanation:

That is the only answer choice that makes the most sense.

±10 = √100; in this case, they want the non-negative value, so it is 10.

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2 years ago

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Give the rule for the translation if the coordinates of the preimage are A(2,-4) B(5,-4) C(5,-2) D(4,-2) E(4,-1) F(3,-1) G(3,-2)

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Answer:

(x, y) ⇒ (x -7, y)

Step-by-step explanation:

The y-coordinates are unchanged. Each x-coordinate of the image is 7 units less than the corresponding pre-image coordinate. As a rule, this is ...

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2 years ago

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What's the answer to this math problem?

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Step-by-step explanation:

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2 years ago

A trapezoid is broken into 2 triangles and 1 rectangle. The triangles both have a base of 2 meters and a height of 5 meters. The

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Answer:

Part 1) The trapezoid has an area of $20\ m^2$

Part 2) The kite has an area of $21\ m^2$

Part 3) The area of the trapezoid is less than the area of the kite

Step-by-step explanation:

Part 1

Find the area of trapezoid

we know that

The area of trapezoid is equal to the area of two congruent triangles plus the area of a rectangle

$A=2[\frac{1}{2} (2)(5)]+(2)(5)$

$A=10+10=20\ m^2$

Part 2

Find the area of the kite

we know that

The area of the kite is equal to the area of two congruent triangles

$A=2[\frac{1}{2} (7)(3)]=21\ m^2$

Part 3

Compare the areas

The trapezoid has an area of $20\ m^2$

The kite has an area of $21\ m^2$

$20\ m^2< 21\ m^2$

therefore

The area of the trapezoid is less than the area of the kite

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3 years ago

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