Let <em>f(x)</em> = <em>x</em>³ + <em>x</em> - 5. <em>f(x)</em> is a polynomial so it's continuous everywhere on its domain (all real numbers). Since
<em>f</em> (1) = 1³ + 1 - 5 = -3 < 0
and
<em>f</em> (2) = 2³ + 2 - 5 = 5 > 0
it follows by the intermediate value theorem that there at least one number <em>x</em> = <em>c</em> between 1 and 2 for which <em>f(c)</em> = 0.
I'M soo not sure on this one. But if I did the math correctly your answer would be C. 64
Hoped I help!
Also sorry if its wrong.
Answer:
2
Step-by-step explanation:
10a² : 5a² = 10 : 5 = 2
Answer:
5
Step-by-step explanation:
=2+(3)(16)-(2)(21)-3
=2+48-(2)(21)-3
=50-(2)(21)-3
=50-42-3
=8-3
=5
Hope this helped! :)
Answer:
A... .................. ....
