Answer:
90$
Step-by-step explanation:
(12 pairs of jeans * $7.50) / 1 pair of jeans = 90$
There are 25 tiles total - triangles or squares - 84 edges
triangle (<em>t</em>) = 3 sides
square (<em>s</em>) = 4 sides
<em>t</em>+<em>s</em>= total tiles
<em><u>t</u></em><u>+</u><em><u>s</u></em><u> = 25 </u>← solve
3<em>t</em> + 4<em>s</em> = total sides
<u>3</u><em><u>t </u></em><u>+ 4</u><em><u>s</u></em><u> = 84</u> ← solve
<em>
</em><em>t </em>= 16 <em>s</em> = 9
Check
16 + 9 = 25
3(16) + 4(9) = 84
48 + 36 = 84
<u>There are 9 square tiles in the box</u>
Time taken by Jami to mow 1/6 acres is 8 minutes=8/60=2/15 hours.
Rate at which Jami is mowing will be:
rate=(number of acres)/(time)=(1/6)/(2/15)
=1/6÷2/15
=1/6×15/2
=5/4 acres/hour
=1.25 acres/hour
From above calculations we conclude that Jami cannot mow 1.5 acres in 1 hour
9514 1404 393
Answer:
2 2/3
Step-by-step explanation:
Let the number be represented by x. Then the problem statement is telling you ...
4 5/9 = 2 1/3 + (5/6)x
You can isolate the x term by subtracting 2 1/3 from both sides of the equation. (The properties of equality require that the same operation be performed on both sides of the equation.)
(4 5/9) - (2 3/9) = (2 3/9) -(2 3/9) +(5/6)x
2 2/9 = (5/6)x
The definition of the multiplicative inverse tells you that the coefficient of x can be made to be 1 if the term is multiplied by (6/5). We must do that to both sides of the equation.
(6/5)(2 2/9) = (6/5)(5/6)x
(6/5)(20/9) = x . . . . simplify
120/45 = x . . . . . . do the multiplication
8/3 = x = 2 2/3 . . . . . . . reduce the fraction
The number is 2 2/3.
_____
<em>Additional comment</em>
The number we're looking for is multiplied by 5/6 and the result has 2 1/3 added to it. To find the number, we "undo" these operations, in reverse order. We undo the addition by subtracting the amount that was added. We undo the multiplication by multiplying by the inverse of that factor.
This is the sort of logic that you would use to fill in the blank for ...
7 = 1 + 3×___
You probably recognize that this breaks down into two problems:
7 = 1 + ___ . . . . . (6 goes in the blank)
and
6 = 3×___
You may notice that for all of these problems, a good knowledge of addition and multiplication facts is useful.