Answer: The correct option is A, itis the product of the initial population and the growth factor after h hours.
Explanation:
From the given information,
Initial population = 1000
Increasing rate or growth rate = 30% every hour.
No of population increase in every hour is,
Total population after h hours is,
It is in the form of,
Where 
is the initial population, r is increasing rate, t is time and [tex(1+r)^t[/tex] is the growth factor after time t.
In the above equation 1000 is the initial population and 
is the growth factor after h hours. So the equation is product of of the initial population and the growth factor after h hours.
Therefore, the correct option is A, itis the product of the initial population and the growth factor after h hours.
Answer:
p = 8000 + 2(6000)
20000
Step-by-step explanation:
Given that:
Profit in 1988 = 6000
Profit in 2003 = 8000 more Than double the profit made in 1998
Hence profit in 2003 (p) can be expressed as :
p = 8000 + 2(6000)
Hence profit in 2003
p = 8000 + 12000
p = 20,000
Answer:
600
Step-by-step explanation:
How to do it in your head (secret):
3*2 = 6
add 2 zeros after the 6 since there are 2 zeros in total in this equation 2<u><em>0 </em></u>and 3<u><em>0</em></u> so:
30*20 = 600
:D
First you Change the mixed number to an improper fraction (14/3) then you simplify (1/4 X 7/3) and then you multiply 1/4 X 7/3 = 7/12 :)
You would use unit rate for this. If Austin makes $209 in 11 hours, then he makes 209/11 = 19 dollars in 1 hour.
Then, we can make a proportion:
$19/1 hour = $152/ x hours
Cross multiply:
152 = 19x
Solve for x to get:
x = 8 hours.
