Ask question

Ask question

All categories

2 years ago

11

During a special sale, all video games cost $26 and all movies cost $14. Derrick plans to spend some or all of his $220 in birth

day money on these movies and video games. Let "x" represet the number of games Derrick can buy and "y" represent the number of movies he can buy. Write the inequality that describes this situation in standard form.

1 answer:

BigorU [14]2 years ago

7 0

Answer:

$13x+7y\leq 110$

Step-by-step explanation:

Let "x" represents the number of games Derrick can buy and "y" represents the number of movies he can buy.

Cost of all video games = $26

Cost of all movies cost = $14

Total amount with Derrick = $220

So,

cost of $x$ video games + cost of $y$ movies $\leq$ 220

Therefore, the inequality is $26x+14y\leq 220$

Divide this inequality by 2

$13x+7y\leq 110$

You might be interested in

In what quadrant is the terminal side<br> of -323°?

dexar [7]

Answer:

Quadrant 4 i believe plz tell me if im wrong

Step-by-step explanatio

6 0

2 years ago

Read 2 more answers

Please help im so confused??

Ann [662]

V = PI x r^2 x h/3

3.14 x 7^2 x 24/3

49 x 8 = 392

answer is 392PI units^3

answer is B

5 0

2 years ago

There are 5 red balls, 4 blue balls, 6 yellow balls and 10 green balls in a box,

lys-0071 [83]

<h2 /><h2>Here we go ~ </h2>

According to given information there are :

5 red balls

4 blue balls

6 yellow balls

10 green balls

<h3>1. what is the probability that the ball chosen is red ?</h3>

-

$\qquad \sf \dashrightarrow \: p(red) = \dfrac{total \: red \: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(red) = \dfrac{5}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(red) = \dfrac{5}{25}$

$\qquad \sf \dashrightarrow \: p(red) = \dfrac{1}{5}$

<h3>2. what is the probability that the ball chosen is blue ?</h3>

$\qquad \sf \dashrightarrow \: p(blue) = \dfrac{total \: blue \: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(blue) = \dfrac{4}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(blue) = \dfrac{4}{25}$

<h3>3. what is the probability that the ball chosen is yellow ?</h3>

$\qquad \sf \dashrightarrow \: p(yellow) = \dfrac{total \: yellow\: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(yellow) = \dfrac{6}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(yellow) = \dfrac{6}{25}$

<h3>4. what is the probability that the ball chosen is green ?</h3>

$\qquad \sf \dashrightarrow \: p(green) = \dfrac{total \: green\: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(green) = \dfrac{10}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(green) = \dfrac{10}{25}$

$\qquad \sf \dashrightarrow \: p(green) = \dfrac{2}{5}$

<h3>5. what is the probability that the ball chosen is not green ?</h3>

$\qquad \sf \dashrightarrow \: p(not \: green) = \dfrac{total \: non \: green\: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(not \: green) = \dfrac{5 + 4 + 6}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(not \: green) = \dfrac{15}{25}$

$\qquad \sf \dashrightarrow \: p(not \: green) = \dfrac{3}{5}$

3 0

1 year ago

Hurry someone please answer plsss<br> Find the midpoint of each line segment.

djverab [1.8K]

Answer:

2.5

Step-by-step explanation:

you can use pythag theorem and divide c by two:

-3^2+4^2=c^2

9+16= 25

c=5

however, 5/2=2.5

4 0

2 years ago

Cost of 10 oranges is one dollar what is the cost of five

aleksley [76]

10 oranges = $1
5 oranges = $?

To get from 10 to 5 you divide by 2 so that’s what you do with the $1 so it would be $0.50

8 0

3 years ago