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Stella [2.4K]
3 years ago
13

THIS IS FOR 19 POINTS!!!

Mathematics
1 answer:
zepelin [54]3 years ago
4 0
1).  To multiply with like bases, add the exponents ===>  5² x 5⁵ = 5⁷

2).  Same rule.  e² x e⁷ = e⁹

3).  Same rule, but make sure to start with like bases.

2a⁵ x 6a = (2 x 6) (a⁵ x a¹) = 12 a⁶

4).  Same rule, but make sure to start with like bases.

4x² (-5)x⁶ = (4) (-5) (x² x⁶) = -20x⁸

5).  To divide with like bases, subtract the denominator (divisor) exponent
from the numerator (dividend) exponent. ===> 7⁹ / 7³ = 7⁶

6).  Same rule.    v¹⁴ / v⁶ = v⁸

7).  Same rule, but make sure to start with like bases.

15w⁷ / 5w² = (15/5) (w⁷/w²) = 3 w⁵

8).  Same rule, but make sure to start with like bases.

10 m⁸ / 2m = (10/2) (m⁸ / m¹) = 5m⁷

9).  Same rules.  Add exponents to multiply, subtract them to divide.

( 2⁵ x 3⁷ x 4³ ) / (2¹ x 3⁵ x 4) = (2⁵ / 2¹) x (3⁷ / 3⁵) x (4³ / 4¹) = 2⁴ x 3² x 4²

10).  (4¹⁵) x (-5)⁶ / (4¹² x (-5)⁴ ) = (4¹⁵/4¹²) x [ (-5)⁶/(-5)⁴ ] = 4³ x (-5)² = 4³ x 5²

11).  (6⁷ x 7⁶ x 8⁵) / (6⁵ x 7⁵ x 8⁴) = (6⁷ / 6⁵) x (7⁶ / 7⁵) x (8⁵ / 8⁴)
       You can finish it from here, you Crazy Unicorn you.

12).  [ (-3)⁶ x 10⁵ ] / [ (-3)⁴ x 10³ ]   =  [ (-3)⁶ / (-3)⁴ ] x (10⁵/10³)  
        The last step is yours.  Take it !
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-3(-5)-3y=-6 find the value of y
julia-pushkina [17]

-3 (-5) - 3y = -6

15 - 3y = -6

-3y = -6 + (-15)

-3y = -21

y = -21 / -3

y = 7

The value of y is 7.

6 0
4 years ago
Find the midpoint of RS<br> a- (-5,3)<br> b- (3,3) <br> c- (-1,3)<br> d-(0,3)
DaniilM [7]
Plug it into the midpoint formula.

x1+x2/2; y1+y2/2

R (-5,4) S (3,2)

-5+3/2; 4+2/2

-2/2; 6/2

(-1,3) or "C"

I hope this helps!
~cupcake
5 0
3 years ago
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What fraction is not equal to 2/3​
Svetllana [295]

Answer:

All fractions except 2/3 lol

Step-by-step explanation:

6 0
3 years ago
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What does 3 ^ 07 equal
never [62]

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2187

Step-by-step explanation:

you multply 3 7 times

7 0
3 years ago
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Solve the equation for x, where x is a real number (5 points): <br> -2x^2 + 5x - 10 = 3
KatRina [158]
Subtract 3 from both sides so that the equation becomes -2x^2 + 5x - 13 = 0.
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
                                      x = [ -b ± √(b^2 - 4ac) ] / (2a)
                                      x = [ -5 ± √((5)^2 - 4(-2)(-13)) ] / ( 2(-2) )
                                      x = [-5 ± √(25 - (104) ) ] / ( -4 )
                                      x = [-5 ± √(-79) ] / ( -4)
Since √-79 is nonreal, the answer to this question is that there are no real solutions.
3 0
3 years ago
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