Plug it into the midpoint formula.
x1+x2/2; y1+y2/2
R (-5,4) S (3,2)
-5+3/2; 4+2/2
-2/2; 6/2
(-1,3) or "C"
I hope this helps!
~cupcake
Answer:
All fractions except 2/3 lol
Step-by-step explanation:
Answer:
2187
Step-by-step explanation:
you multply 3 7 times
Subtract 3 from both sides so that the equation becomes -2x^2 + 5x - 13 = 0.
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
x = [ -b ± √(b^2 - 4ac) ] / (2a)
x = [ -5 ± √((5)^2 - 4(-2)(-13)) ] / ( 2(-2) )
x = [-5 ± √(25 - (104) ) ] / ( -4 )
x = [-5 ± √(-79) ] / ( -4)
Since √-79 is nonreal, the answer to this question is that there are no real solutions.