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4 years ago

Fill the blank ___sinb=(1)/(2)[sin(a+b)-sin(a-b)] There are no answer choices

Mathematics

1 answer:

Serga [27]4 years ago

5 0

Sin b=1/2
Sin(a+b)-sin(a-b)
Sina+Sinb-Sina+Sinb
2Sinb
2×1/2
=1

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1) Brandon owns nearly 2 times as many CDs as Ingrid. Brandon owns 56 CDs. Write an equation and use it to estimate the number "

Arisa [49]

1)n=2(56)

2)x=5
If u need to show work it would be like this****

(-1/13)-13x=-65(-1/13)
X=5

8 0

3 years ago

Thanks you to those who have been helping me with my math homework much appreciation have these points as gratitude!

7nadin3 [17]

Answer:

cool

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Please help with math problem

e-lub [12.9K]

Answer:

$a_0 = -8$

$a_1=-6$

$x^2 +y^2 -8x - 6y = 0$

Step-by-step explanation:

The equation of the circle has the following form

$x^2 + y^2 + a_0x + a_1y=0$

The equation of the circle has the following form

We know that the circle goes through the following points

(1, 7)

(8, 6)

(7, -1).

Then we substitute the values of x and y in the equation

For (1, 7)

$(1)^2 + (7)^2 + a_0(1) + a_1(7)=0$

$1 + 49 + a_0 + 7a_1=0$

$a_0 + 7a_1=-50$ (1)

For (8, 6)

$(8)^2 + (6)^2 + a_0(8) + a_1(6)=0$

$64 + 36 + 8a_0 + 6a_1=0$

$8a_0 + 6a_1= -100$ (2)

With these equations is enough to solve the system

$a_0 + 7a_1=-50$ (1)

$8a_0 + 6a_1= -100$ (2)

Multiply the equation (1) by -8 and add it to the equation (2)

$-8a_0 - 56a_1=400$ (1)

$8a_0 + 6a_1= -100$ (2)

-----------------------------------------------------

$-50a_1 = 300\\\\a_1 = -6$

Then

$a_0 + 7(-6) = -50\\\\a_0 = -50+42\\\\a_0=-8$

Finally the equation is:

$x^2 +y^2 -8x - 6y = 0$

7 0

3 years ago

Geometry: If you are right I'll give brainliest

iVinArrow [24]

Answer:

Step-by-step explanation:

Looks like we both struggle with geometry

3 0

3 years ago

Can someone help me with this question?

belka [17]

Answer:

The required probability is 0.0155.

Step-by-step explanation:

We are given that the one-year survival rate for pancreatic cancer is 20%.

Of 12 people diagnosed with pancreatic cancer at one hospital, 6 survived one year.

The above situation can be represented through binomial distribution;

$P(X=r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,......$

where, n = number of trials (samples) taken = 12 people

r = number of success = 6 survived

p = probability of success which in our question is probability of

one-year survival rate for pancreatic cancer, i.e; p = 20%

Let X = Number of people survived one year

So, X ~ Binom(n = 12 , p = 0.20)

Now, the probability that 6 survived one year is given by = P(X = 6)

P(X = 6) = $\binom{12}{6} \times 0.20^{6} \times (1-0.20)^{12-6}$

= $924 \times 0.20^{6} \times 0.80^{6}$

= 0.0155

5 0

4 years ago