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KiRa [710]
3 years ago
9

Sq root 30

Mathematics
2 answers:
AfilCa [17]3 years ago
7 0

Answer:

good luck

Step-by-step explanation:

Trava [24]3 years ago
3 0

Answer:

C

Step-by-step explanation:

this is the answer

it is irrational because it cannot be expressed in a ratio of two integers

please give me brainliest .

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What is the missing number in the line 415,418,423,427,430
mihalych1998 [28]
This is a good question... but is there multiple choice, i want to know if my answer matches
8 0
3 years ago
Solve the system of eqautions <br> y=x2-5x+7 , y=2x+1
IgorC [24]

Answer:

Step-by-step explanation:

The system of equations is given as

y=x^2-5x+7 - - - - - - - - - - 1

y=2x+1 - - - - - - - - - - - - - - 2

We would equate equation 1 to equation 2, it becomes

x^2-5x+7 = 2x+1

x^2-5x+7- 2x - 1 = 0

x^2-5x+7- 2x - 1 = 0

x^2 - 5x - 2x + 7 - 1 = 0

x^2 - 7x + 6 = 0

We would use the factorization method of solving quadratic equations.

x^2 - 6x - x + 6 = 0

x(x - 6) - 1(x - 6)

(x - 6)(x - 1) = 0

x - 6 = 0 or x - 1 = 0

x = 6 or x = 1

Substituting both values of x into equation 2, it becomes

For x = 6,

y=2×6 + 1 = 12 + 1 = 13

y = 13

For x = 1,

y=2 × 1 +1 = 2 + 1 = 3

y = 3

3 0
3 years ago
A model length of 12 cm. represents an actual length of 102 ft.the model has a width of 48cm. What is the width of the actual ob
Elodia [21]

the answer would be 408


just set it up like this

12       48

----  =  ----

102      ?


12*4=48 so 102*4 = 408

8 0
3 years ago
What is the equation of a circle with center (-2, 3) and radius 4?
Bad White [126]
Hello,

(x+2)²+(y-3)²=16
5 0
3 years ago
(x-1)(x-3)(x+5)(x+7)=297
mihalych1998 [28]

First simplify the expression into polynomial form,

(x-1)(x-3)(x+5)(x+7)=297

x^4+8x^3-10x^2-104x+105=297

x^4+8x^3-10x^2-104x-192=0

Now factor into,

(x-4)(x+8)(x^2+4x+6)=0

Which means the solutions are,

x-4=0\implies\boxed{x_1=4}

x+8=0\implies\boxed{x_2=-8}

and then two complex solutions because determinant of the third factor D\lt0,

x^2+4x+6=0

x^2+4x+4=-2

(x+2)^2=-2\implies\boxed{x_3=i\sqrt{2}-2},\boxed{x_4=-i\sqrt{2}-2}

Hope this helps :)

5 0
3 years ago
Read 2 more answers
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