Answer:
Step-by-step explanation:
Given the first two numbers of a sequence as 2, 6...
If it is an arithmetic difference, the common difference will be d = 6-2 = 4
Formula for calculating nth term of an ARITHMETIC sequence Tn = a+(n-1)d
a is the first term = 2
d is the common difference = 4
n is the number if terms
Substituting the given values in the formula.
Nth term Tn = 2+(n-1)4
Tn = 2+4n-4
Tn = 4n-4+2
Tn = 4n-2
2) If the sequence us a geometric sequence
Nth term of the sequence Tn = ar^(n-1)
r is the common ratio
r is gotten by the ratio of the terms I.e
r = T2/T1
r = 6/2
r = 3
Since a = 2
Tn = 2(3)^(n-1)
Hence the nth term of the geometric sequence is Tn = 2(3)^(n-1)
A. Y=x+2
I thinks that’s right hope this helps :)
Answer:
(-1)(11)(3)(5)
Step-by-step explanation:
First off: -165 separates into the factors (-1) and (165). Next, we divide 165 by 15, obtaining 15(11).
So far, we have (-1)(11)(15).
15 is still factorable. We get:
(-1)(11)(3)(5), which is the desired prime factorization of -165.
Answer:
You can sell at least 40 phones each week.
Step-by-step explanation:
Given that:
Weekly base salary = $150
Earning on each phone = $20
Maximum amount that can be earned each week = $950
Let,
m be the number of phones.
20m + 150 ≤ 950
20m ≤ 950 - 150
20m ≤ 800
Dividing both sides by 20
m ≤ 40
Hence,
You can sell at least 40 phones each week.
Answer:
3 cups
Step-by-step explanation:
we can solve this by setting up ratios
cross multiply:
solve for x
