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konstantin123 [22]
4 years ago
13

What is the frequency of the sinusoidal graph?

Mathematics
1 answer:
motikmotik4 years ago
8 0

Answer:

\frac{3}{2\pi}.

Step-by-step explanation:

We are given the graph of a sinusoidal function.

From the graph we see that,

The given graph is represented by the function f(x)=\sin(3x)

<em>Now, 'If a function f(x) is of period P, then f(bx) has period \frac{P}{|b|}'.</em>

So, we get,

As, f(x)=\sin(x) have period 2\pi.

Then, f(x)=\sin(3x) have period \frac{P}{|3|} i.e. \frac{2\pi}{3}.

Since, 'Frequency is the reciprocal of the period',

We have,

Frequency of the given function is \frac{3}{2\pi}.

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Answer:

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4 years ago
The quantity of four minus one all raised to the five-minus- two power
leva [86]

Answer:

(4-1)^5-2

Step-by-step explanation:

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3 years ago
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7 to the 6th power = n to the 8th power what is n
Valentin [98]

Answer:

n=7 3/4, -7 3/4

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4 years ago
What is the nth term?
kumpel [21]

Let a_k denote the <em>k</em>th term of the sequence. Then

a_k=a_1+d(k-1)

where <em>d</em> is the common difference between consecutive terms in the sequence and <em>a</em>₁ is the first term.

The sum of the first <em>n</em> terms is

S_n=\displaystyle\sum_{k=1}^na_k=a_1+a_2+\cdots+a_{n-1}+a_n

From the formula for a_k, we get

S_n=\displaystyle\sum_{k=1}^n(a_1+d(k-1))=a_1\sum_{k=1}^n1+d\sum_{k=1}^n(k-1)

S_n=\displaystyle na_1+d\sum_{k=0}^{n-1}k

S_n=na_1+\dfrac{d(n-1)n}2

S_n=\dfrac n2(2a_1-d+dn)

So we have d=-5, and 2a_1-d=16 so that a_1=\frac{11}2.

Then the <em>n</em>th term in the sequence is

a_n=\dfrac{11}2-5(n-1)=\boxed{\dfrac{21-10n}2}

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4 years ago
Find the area in the right tail more extreme than z= 3.01 in a standard normal distribution
Feliz [49]
<span>The area in the right tail more extreme than z= 3.01 in a standard normal distribution is given by

P(z > 3.01) = 1 - P(z < 3.01) = 1 - 0.99869 = 0.00131
</span>
5 0
3 years ago
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