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3 years ago

Put the following numbers in order (from largest to smallest): -55.5, -12.2, -12, -55

Mathematics

2 answers:

Semmy [17]3 years ago

6 0

Answer:

-12.2, -12, -55.5 and -55

vivado [14]3 years ago

5 0

Answer:

Hey mate......

This is ur answer......

-55.5< -55< -12.2< -12

hope it helps,

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Kate prepared 9 kilograms of dough after working 3 hours. How many hours did Kate work if she prepared 12 kilograms of dough? As

beks73 [17]

Answer:

4 hours

Step-by-step explanation:

cross multiply

3 0

3 years ago

PLEASE HELP god bless Justify each step of the solution by stating the property that was used to get to each step. Given: 4(-6x

baherus [9]

4(-6x – 3) + 24x = -72x + 132

Step 1 -24x – 12 + 24x = -72x + 132 Distribute Property of Equality

Step 2: –12 = -72x + 132 equivalent

Step 3: -144 = -72x Subtraction Property of equality

Step 4: 2 = x Equivalent / Division property of equality

6 0

4 years ago

Let X be a Bernoulli rv with pmf as in Example 3.18. a. Compute E(X2 ). b. Show that V(X) 5 p(1 2 p). c. Compute E(X79).

spayn [35]

The Bernoulli distribution is a distribution whose random variable can only take 0 or 1

The value of E(x2) is p
The value of V(x) is p(1 - p)
The value of E(x79) is p

<h3>How to compute E(x2)</h3>

The distribution is given as:

p(0) = 1 - p

p(1) = p

The expected value of x2, E(x2) is calculated as:

$E(x^2) = \sum x^2 * P(x)$

So, we have:

$E(x^2) = 0^2 * (1- p) + 1^2 * p$

Evaluate the exponents

$E(x^2) = 0 * (1- p) + 1 * p$

Multiply

$E(x^2) = 0 +p$

Add

$E(x^2) = p$

Hence, the value of E(x2) is p

<h3>How to compute V(x)</h3>

This is calculated as:

$V(x) = E(x^2) - (E(x))^2$

Start by calculating E(x) using:

$E(x) = \sum x * P(x)$

So, we have:

$E(x) = 0 * (1- p) + 1 * p$

$E(x) = p$

Recall that:

$V(x) = E(x^2) - (E(x))^2$

So, we have:

$V(x) = p - p^2$

Factor out p

$V(x) = p(1 - p)$

Hence, the value of V(x) is p(1 - p)

<h3>How to compute E(x79)</h3>

The expected value of x79, E(x79) is calculated as:

$E(x^{79}) = \sum x^{79} * P(x)$

So, we have:

$E(x^{79}) = 0^{79} * (1- p) + 1^{79} * p$

Evaluate the exponents

$E(x^{79}) = 0 * (1- p) + 1 * p$

Multiply

$E(x^{79}) = 0 + p$

Add

$E(x^{79}) = p$

Hence, the value of E(x79) is p

Read more about probability distribution at:

brainly.com/question/15246027

5 0

3 years ago

What is the value of the expression shown below? Plssssss helppppp

Mandarinka [93]

I think it’s 8 but unsure

8 0

2 years ago

Help me please :) thank you

Ghella [55]

Answer:

do 10 20 20 40 50

Step-by-step explanation:

hope it helps sorry if it does not if not then try 1 2 3 4 5

6 0

3 years ago