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sdas [7]
3 years ago
6

A particular airline wants to know how its customers feel about its service. Every day during the survey period, it randomly sel

ects 10 flights, and asks all of the passengers on these flights to fill out a short questionnaire. This type of sampling design is called____________.
Mathematics
1 answer:
-BARSIC- [3]3 years ago
5 0

Answer:

Cluster Random Sample

Step-by-step explanation:

another example should help

Example—An airline company wants to survey its customers one day. So they randomly select 5 flights that day and survey every passenger on those flights, it's a cluster random Sample

it's kinda similar

hope it helps

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2x + x = 135
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Silicone implant augmentation rhinoplasty is used to correct congenital nose deformities. The success of the procedure depends o
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<h2><u>Answer with explanation:</u></h2>

Let \mu be the population mean strain in a way that conveys information about precision and reliability.

The sample mean is the best point estimate of the true population mean .

As per given , we have

Sample size : n= 12

degree of freedom : df=12-1=11

Sample mean : \overline{x}=25.0

The true average strain in a way that conveys information about precision and reliability= 25.0

sample standard deviation : s= 3.3

Significance level : \alpha= 0.05

Since sample population standard deviation is unknown , so we use t-test.

Critical t-value for t : t_{\alpha/2, df}=t_{0.025, 11}=2.201

95% Confidence interval for true average strain in a way that conveys information about precision and reliability:

\overline{x}\pm t_{\alpha/2, df}\dfrac{s}{\sqrt{n}}

25.0\pm (2.201)\dfrac{3.3}{\sqrt{12}}\\\\=\approx 25.0\pm2.10\\\\=(25.0-2.10, 25.0+2.10)=(22.9,\ 27.1)

The 95% Confidence interval for true average strain in a way that conveys information about precision and reliability: (22.9,\ 27.1)

We 95% confident that the true population average strain in a way that conveys information about precision and reliability lies between 22.9 and 27.1 .

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4 years ago
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<h2>Answer:</h2>

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<h2>Step-by-step explanation:</h2>

As the question states,

John's brother has Galactosemia which states that his parents were both the carriers.

Therefore, the chances for the John to have the disease is = 2/3

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Martha's great-grandmother also had the disease that means her children definitely carried the disease means probability of 1.

Now, one of those children married with a person.

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Now, again the child's child (Martha) probability for having the disease is = 1/2.

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<u>The total probability for Martha's first child to be diagnosed with Galactosemia will be,</u>

Probability=\frac{2}{3}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{4}\\Probability=\frac{1}{24}

(Here, we assumed that the child has the disease therefore, the probability was taken to be = 1/4.)

<em><u>Hence, the probability for the first child to have Galactosemia is \frac{1}{24}</u></em>

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