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Svetlanka [38]
3 years ago
9

Which of the following steps were applied to abc obtain a'b'c'

Mathematics
2 answers:
Luba_88 [7]3 years ago
7 0

Answer:

Shifted 2 units left and 4 units up

Step-by-step explanation:

Given are two triangles

ABC is having vertices as (4,6) (7,6) and (5,9)

The transformed image A'B'C' has vertices as

(2,10) (5,10) (3,13)

On comparing the vertices corresponding we find a certain pattern.

X coordinate is reduced by 2 and y coordinate is increased by 4.

This implies the transformation is

Shifted 2 units left and 4 units up

Helen [10]3 years ago
6 0
D) shifted 2 units left and 4 units up

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The length of a rectangle is 15 and its width is w.
Fed [463]

A rectangle with sides 15 and w has perimeter

2p = 2(15+w) = 2w+30

We want this quantity to be at most 50, so it must be less than or equal to 50:

2w+30\leq 50

For the record, this implies that

2w\leq 20 \iff w \leq 10

So, the width can be at most 10.

6 0
3 years ago
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Having a small brain moment, can you please help and show work
ankoles [38]

Answer:

The value if x is 0.9875.

Step-by-step explanation:

First, we have to get rid of brackets by expanding :

0.5(2x +  \frac{3}{4} ) -  \frac{1}{3} (0.1 + x) = 1

0.5(2x) + 0.5( \frac{3}{4} ) -  \frac{1}{3} (0.1) -  \frac{1}{3} (x) = 1

x +  \frac{3}{8}  -  \frac{1}{30}   -   \frac{1}{3} x = 1

Next you have to collect like terms :

x  -  \frac{1}{3} x +  \frac{3}{8}  -  \frac{1}{30}  = 1

\frac{2}{3} x +  \frac{41}{120}  = 1

Lastly, you can solve x :

\frac{2}{3} x = 1 -  \frac{41}{120}

\frac{2}{3} x =  \frac{79}{120}

x =  \frac{79}{120}  \div  \frac{2}{3}

x =  \frac{79}{80}

x = 0.9875

8 0
2 years ago
Jack said, "five times my age in 2 years is 100." <br> How old is jack now?
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Answer:

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Step-by-step explanation:

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Set up a proportion for the situation and solve for the unknown quantity. Round to the hundredths place because we are dealing with money.

See details:

4 0
11 months ago
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