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PtichkaEL [24]
3 years ago
9

Determine the measure of ∠Q, rounded to the nearest tenth of a degree. images attached.

Mathematics
1 answer:
const2013 [10]3 years ago
8 0

Answer:

D

Step-by-step explanation:

Using the Sine rule in Δ QRS , that is

\frac{q}{sinQ} = \frac{r}{sinR} , that is

\frac{15}{sinQ} = \frac{12}{sin50.1} ( cross- multiply )

12× sinQ = 15 × sin50.1° ( divide both sides by 12 )

sinQ = \frac{15sin50.1}{12} , thus

Q = sin^{-1} ( \frac{15sin50.1}{12} ) ≈ 73.5° ( to the nearest tenth )

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4 0
3 years ago
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