Question

Determine the measure of ∠Q, rounded to the nearest tenth of a degree. images attached.

Answer 1

Answer:

D

Step-by-step explanation:

Using the Sine rule in Δ QRS , that is

$\frac{q}{sinQ}$ = $\frac{r}{sinR}$ , that is

$\frac{15}{sinQ}$ = $\frac{12}{sin50.1}$ ( cross- multiply )

12× sinQ = 15 × sin50.1° ( divide both sides by 12 )

sinQ = $\frac{15sin50.1}{12}$ , thus

Q = $sin^{-1}$ ( $\frac{15sin50.1}{12}$ ) ≈ 73.5° ( to the nearest tenth )