F ufufbuffbfubff ffuvfubf u ufff in I buddy ffbuffffffuffffuvuffufffffu fff ffuff. I I I I f if I c f if i. F. I. If c I g it if iii. If I I. Uf. G. If. F. Gg. F. F if I. F f f fff fu f uI fiuuf u if I. Fru I ffif. Fuf fff fff fffffffffffffffffffffffffffffffffffffffffffffffffhfffffufuffffu ffffu fffufb hug FF difficulty fffffffffhffufffgu g g. Gg. Ugh. I. I. G. Hi. H I g g. Yes g hi gi c cighow gg cig. Cu f. Fci. I. I. I. Cffcfi. I c. CYes c. Cc. Ccc I. I. Cci gYes cfci i
x = 
isolate 5x by adding c to both sides of the equation
5x = k + c ( divide both sides by 5 )
x = 
Answer:
Step-by-step explanation:
If you want the mid point for these questions then for the 1st
1. add -6 and -2 which is -8 then divide by 2 which is -4, then add -1 and -3 which is -4 and then divide by 2 which is -2. so the mid point is (-4,-2)
2. its the same as above first add -4 and 2 which is -2 then divide by 2 which is -1, then add -5 and 3 which is -2 and divide by 2 which is -1. the point is (-1,-1)
3. -3+3=0 dived by 2 which is 0, -1+5=4 divide by 2 which is 2
point is (0,2)
4. -3+4=1 divide by 2 which is 1/2 =0.5, -2+7=5 then divide by 2 which is 5/2=2.5. point is (0.5,2.5)
It can't be factored because there are no 2 numbers that when you multiply you get 35 and when you add you get 13.
Answer: c. Level of Significance
This is the alpha value
alpha is a greek letter with the symbol 
A type 1 error is when the researcher rejects the null, but the null was true (meaning the researcher shouldn't have rejected the null).