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chubhunter [2.5K]
3 years ago
6

The diagonal of a rectangle is 25 in. The width is 15 in. What is the area of the triangle?

Mathematics
1 answer:
Vikki [24]3 years ago
3 0
First, find the length
L^2+W^2=D^2 )L for length, W for width, D for diagonal)
L^2=25^2-15^2=625-225=400
L=20
A=1/2 of L*W= (1/2)*20*15=150 square inches
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Answer:

3. 150.72 in²

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Step-by-step Explanation:

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The surface area = Area of the 2 circles + area of the rectangle

Take π as 3.14

radius of circle = ½ of 4 = 2 in

Area of the 2 circles = 2(πr²) = 2*3.14*2²

Area of the 2 circles = 25.12 in²

Area of the rectangle = L*W

width is given as 10 in.

Length (L) = the circumference or perimeter of the circle = πd = 3.14*4 = 12.56 in

Area of rectangle = L*W = 12.56*10 = 125.6 in²

Surface area of net = Area of the 2 circles + area of the rectangle

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4. Surface area of the net (S.A) = 2(area of triangle) + 3(area of rectangle)

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Where,

b = 8 cm

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Step-by-step explanation:

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Step-by-step explanation:

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I really hope this helps!

-SpaceMarsh

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Read 2 more answers
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