Answer:
Option 4. x = 0
Step-by-step explanation:
we know that
The rule of the reflection of a point across the y-axis is equal to
(x,y) -----> (-x,y)
The rule for reflecting over the Y axis is to negate the value of the x-coordinate of each point, but leave the y-value the same
The coordinates of triangle PQR are
P(1, 4), Q(3, 6), and R(5, 2)
Applying the rule of the reflection across the y-axis we have
P(1, 4) -----> P'(-1, 4)
Q(3, 6) ----> Q'(-3, 6)
R(5, 2)----> R'(-5, 2)
The reflection line is the y-axis
Remember that the equation of the y-axis is x=0
therefore
The equation of the reflection line is x=0
I am not for sure how to do this just yet when I figher it out I will try to help you.<span />
Answer:
c 364
Step-by-step explanation:
this is the correct answer because the rest are lower answers
Note that we can also write equations for circles<span>, </span>ellipses, and hyperbolas<span> in terms of cos and sin, and other </span>trigonometric functions<span>; there are examples of these ...</span>
∠1 = ∠2
2x +10 = 3x -6
16 = x . . . . . . . . . . . add 6-2x
Selection B is appropriate.
