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BaLLatris [955]
3 years ago
10

Can someone please. Help, thanks

Mathematics
2 answers:
erastovalidia [21]3 years ago
7 0

Answer:

Do you mean like on the line it would be x=3 or where you looking for a different type of answer?sorry if this isn't too helpful

Step-by-step explanation:

lilavasa [31]3 years ago
6 0

Answer:

x=3

Step-by-step explanation:

x=5

D:[5]

R:(-∞,+∞)

since this equation represents a vertical line, slope of x is undefined, then, slope of line passing through 3,-10 is undefined too, since it is parallel

the equation of the second line is

y=undefined(3)

x=3

D:[3]

R:(-∞,+∞)

this is vertical line passing the x axis at 3

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MArishka [77]

Answer:

p (x) = x^{3} - 21x^{2}+ 147x - 343

is the required polynomial with degree 3 and p ( 7 ) = 0

Step-by-step explanation:

Given:

p ( 7 ) = 0

To Find:

p ( x ) = ?

Solution:

Given p ( 7 ) = 0 that means substituting 7 in the polynomial function will get the value of the polynomial as 0.

Therefore zero's of the polynomial is seven i.e 7

Degree : Highest raise to power in the polynomial is the degree of the polynomial

We have the identity,

(a -b)^{3} = a^{3}-3a^{2}b +3ab^{2} - b^{3}

Take a = x

        b = 7

Substitute in the identity we get

(x -7)^{3} = x^{3}-3x^{2}(7) +3x(7)^{2} - 7^{3}\\(x -7)^{3} = x^{3}-21x^{2} +147x - 343

Which is the required Polynomial function in degree 3 and if we substitute 7 in the polynomial function will get the value of the polynomial function zero.

p ( 7 ) = 7³ - 21×7² + 147×7 - 7³

p ( 7 ) = 0

p (x) = x^{3} - 21x^{2}+ 147x - 343

4 0
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