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BaLLatris [955]
4 years ago
10

Can someone please. Help, thanks

Mathematics
2 answers:
erastovalidia [21]4 years ago
7 0

Answer:

Do you mean like on the line it would be x=3 or where you looking for a different type of answer?sorry if this isn't too helpful

Step-by-step explanation:

lilavasa [31]4 years ago
6 0

Answer:

x=3

Step-by-step explanation:

x=5

D:[5]

R:(-∞,+∞)

since this equation represents a vertical line, slope of x is undefined, then, slope of line passing through 3,-10 is undefined too, since it is parallel

the equation of the second line is

y=undefined(3)

x=3

D:[3]

R:(-∞,+∞)

this is vertical line passing the x axis at 3

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Which factorization is equivalent to this expression?
grigory [225]

Answer:

10(3x+7)

Step-by-step explanation:

we have the expression:

30x + 70

To factor this expression we need to indentify the components that are common in both terms.

At first glance there is nothing in common, but we can notice that 30 and 70 are multiples of 10, that is:

10*3=30\\10*7=70

so we can substitute this into the expression:

10*3x+10*7

and now that we have the common term (the number 10) we can factorize it, that is, take out the common term and include a parentheses:

10(3x+7)

8 0
3 years ago
the slope of a line passing through h (-2, 5) is -3/4. Which ordered pair represents a point on this line? ​
rosijanka [135]

Answer:

A

Step-by-step explanation:

Calculate the slope of the given points with the point (- 2,  5 )

If the slope is - \frac{3}{4} then the point is on the line

Calculate slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (6, - 1)

m = \frac{-1-5}{6+2} = \frac{-6}{8} = - \frac{3}{4} ← point (6, - 1) is on the line

Repeat with (x₁, y₁ ) = (- 2, 5 ) and (x₂, y₂ ) = (2, 8)

m = \frac{8-5}{2+2} = \frac{3}{4} ← point (2, 8) is not on the line

Repeat with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (- 5, 1)

m = \frac{1-5}{-5+2} = \frac{-4}{-3} = \frac{4}{3} ← point (- 5, 1) is not on the line

Repeat with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (1, 1)

m = \frac{1-5}{1+2} = - \frac{4}{3} ← point (1, 1) is not on the line

Thus the point on the line is (6, - 1 ) → A

4 0
3 years ago
Plutonium-240 decays according to the function where Q represents the quantity remaining after t years and k is the decay consta
taurus [48]
Note: a radioactive decay constant is always negative.

time = [natural log(ending amount / beginning amount)] / k
time = ln (20 / 24) / -.00011
time = ln (5/6) / -.00011
time = -.018232155683 / -.00011
time = <span> <span> <span> 165.7468698455 </span> </span> </span>
time = <span> <span> <span> 165.75 years

</span></span></span>

7 0
3 years ago
Read 2 more answers
Expand, simplify..... :- /
balu736 [363]

Simplifying makes a algebric expression easily understandable and solvable.

5 0
3 years ago
Find the reference angle given: t= -5π/3.
Elina [12.6K]

Answer:

The reference angle is \frac{\pi}{3}

Step-by-step explanation:

The given angle is t=-\frac{5\pi}{3}

The reference angle is the acute angle, that a given angle  makes with the x-axis.

First let us make a sketch of the given angle. <em>See diagram in attachment.</em>

Let \theta be the reference angle of  t=-\frac{5\pi}{3}


Then, from the diagram, we need to subtract \theta from -\frac{5\pi}{3} to get to -2\pi.


We can therefore write the following equation and solve for \theta.


\Rightarrow -\frac{5\pi}{3}-\theta=-2\pi


We group like terms to get,

\Rightarrow -\theta=-2\pi +\frac{5\pi}{3}

We collect LCM to get,

\Rightarrow -\theta=\frac{-6\pi+5\pi}{3}

We simplify to get,

\Rightarrow -\theta=-\frac{\pi}{3}

We divide through by -1

\theta=\frac{\pi}{3} to get,

The correct answer is D.







4 0
3 years ago
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